All categories

3 years ago

Select the fraction that is equivalent to 0.0368.

1 answer:

defon3 years ago

5 0

Since the last number past the decimal is in the ten thousands place, the faction would then be 368/10,000 which can then be reduced to lowest terms to 23/625.

*If you have any questions on how this was solved, please ask me! I'd be happy to help anytime!

You might be interested in

Help, i've been trying for around 30mins and I can't figure it out.

omeli [17]

Answer:

<h2>Option A and C</h2>

Step-by-step explanation:

As,

$2 \sqrt{75} + 3 \sqrt{50}$

$= 2 \sqrt{25 \times 3} + 3 \sqrt{25 \times 2} (A)$

$= 2 \times 5 \sqrt{3} + 3 \times 5 \sqrt{2}$

$= 10 \sqrt{3} + 15 \sqrt{2} (C)$

6 0

3 years ago

Read 2 more answers

Jillian's puppy weighed 16 pounds at the age of 2 months. It weighed 60 pounds at the age of 8 months. What is the percent chang

mel-nik [20]

Answer:the percent change in the puppy's weight= 275%

Step-by-step explanation:

Jillian's puppy Weight at 2 months =16 pounds

Jillian's puppy Weight at 8 months =60 pounds

percent change in the puppy's weight= change in weight / Old weight x 100

(60 pounds -16pounds ) / 16 x 100

44/16 x 100 = 275%

6 0

3 years ago

Every morning Jenna runs for 20 min . If Jenna runs 6 miles per hour , how far does she travel

DerKrebs [107]

20 minutes* (1 hour/ 60 minutes)* (6 miles/ 1 hour)= 2 miles.
(Note that the units cancel out so you end up getting the answer)

The final answer is 2 miles~

6 0

3 years ago

If the Math Olympiad Club consists of 11 students, how many different teams of 3 students can be formed for competitions?

vivado [14]

Answer:

165 different teams of 3 students can be formed for competitions

Step-by-step explanation:

Combinations of m elements taken from n in n (m≥n) are called all possible groupings that can be made with the m elements so that:

Not all items fit
No matter the order
Elements are not repeated

That is, a combination is an arrangement of elements where the place or position they occupy within the arrangement does not matter. In a combination it is interesting to form groups and their content.

To calculate the number of combinations, the following expression is applied:

$C=\frac{m!}{n!*(m-n)!}$

It indicates the combinations of m objects taken from among n objects, where the term "n!" is called "factorial of n" and is the multiplication of all the numbers that go from "n" to 1.

In this case:

n: 3
m: 11

Replacing:

$C=\frac{11!}{3!*(11-3)!}$

Solving:

$C=\frac{11!}{3!*8!}$

being:

3!=3*2*1=6
8!=8*7*6*5*4*3*2*1=40,320
11!=39,916,800

So:

$C=\frac{39,916,800}{6*40,320}$

C= 165

165 different teams of 3 students can be formed for competitions

3 0

3 years ago

For the triangles described, which of the following statements must be true? In triangle DEF, DE=8 in., DF=23 in., and ∡D=16°. I

Temka [501]

Answer:

∠Q≅∠F

Step-by-step explanation:

Two triangles are said to be congruent if all the three sides of the triangles are equal and all the three angles are equal.

Given that: In triangle DEF, DE=8 in., DF=23 in., and ∡D=16°. In triangle PQR, PQ=23 in., PR=8 in., and ∡P=16°.

Hence we can say that ΔDEF is congruent to ΔPQR. According to the side-angle-side (SAS) triangle congruence theorem: If two sides and the included angle of one triangle are equal to two sides and the included angle of another triangle, the triangles are congruent.

Therefore:

DF = PQ, DE = PR, EF = RQ, ∠D = ∠P, ∠E = ∠R and ∠F = ∠Q

7 0

3 years ago