Answer:
28.
a. false
b. true
c. false
d. false
2. 8.4 X 2.3 X 2.09 = 40.3788
3. $10.04 - $13.47
4. Your friend would be incorrect because their decimal is in the wrong place. Take the decimals out of it and think about it. Can 1 times 2 equal anything near 31? no, so it's not reasonable that your friend could multiply 1.2 X 2.6 and get anything near 31.2
5. It is more reasonable to say between 5 and 6 because even when you round both of the numbers up (3 X 2), you still only get 6.
Step-by-step explanation:
ill put it in the comments so I can get this to you faster.
Answer:
(14a+3, 21+4) = 1
Step-by-step explanation:
We are going to use the Euclidean Algorithm to prove that these two integers have a gcd of 1.
gcd (14a + 3, 21a + 4) = gcd (14a+3, 7a + 1) = gcd (1, 7a+1) = 1
Therefore,
(14a + 3, 21a + 4) = 1
F(x) = 3x + 11
Is the function used to show this.
when you know this, you are able to do the following:
f(10) = 30 + 11 = $41
That would be the allowance of the 10th week.
The question, however wants the total.
This again, can be done like this:
f(1) + f(2) + f(3) + f(4) + f(5) + f(6) + f(7) + f(8) + f(9) + f(10) = $275 :)
14 + 17 + 20 + 23 + 26 + 29 + 32 + 35 + 38 + 41 = $275
Sure there is a better formula, but i couldnt seem to make it, sorry.
HUGE UPDATE: The sum is $275 not 200..
Answer:
I think the question is not correct because it can't be factorize
Step-by-step explanation:
Answer:
Average speed of the particle is 13 miles per hour.
Step-by-step explanation:
From the given question expression for distance traveled by the particle is
Then fro the time interval (1, 4) we have to calculate the average speed.
At t=1, s=2(1)²+3(1) =2+3 =5 miles
And at t = 4 s=2(4)²+3(4) = 2(16)+12 = 32+12 =44 miles
So displacement of the particle in the time span from 1 to hours.
s = (44-5) = 39 miles
And the times taken = (4-1) =3 hours
From the formula speed = displacement/(time taken for displacement)
V = 39/3 = 13 miles/hour
