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VashaNatasha [74]
3 years ago
12

Simplify: -0.8b+4.1c-(-3.2b)-0.1c

Mathematics
1 answer:
BigorU [14]3 years ago
8 0

[ Answer ]

\boxed{2.4b \ + \ 4c}

[ Explanation ]

  • Simplify: -0.8b + 4.1c - (-3.2b) - 0.1c

-----------------------------------

  • Apply Rule: - (-a) = a

-0.8b + 4.1c + 3.2b - 0.1c

  • Group Like Terms

-0.8b + 3.2b + 4.1c - 0.1c

  • Add Similar Elements: -0.8b + 3.2b = 2.4b

2.4b + 4.1c - 0.1c

  • Add Similar Elements: 4.1c - 0.1c = 4c

2.4b + 4c

\boxed{[ \ Eclipsed \ ]}

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Sedbober [7]

The given exponential function can be used to determine the

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1. 200

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4. Range; [0, ∞)

Domain: [200, ∞)

5. 346 fishes (approximate value)

<h3>How is the population of the fish obtained from the exponential function?</h3>

The given function is f(x) = 200·(1.05)ˣ

1. The initial population is given by the value of the function when x = 0,

which is given as follows;

At x = 0, f(0) = 200·(1.05)⁰ = 200

  • The initial population of the fish is <u>200</u>

2. The rate of growth of the fish from the exponential function is given as follows;

The growth factor = 1.05

  • The growth rate =<u> 0.05</u>

3. Please find attached the graph of the exponential function created

with MS Excel.

The asymptote of the exponential function is the line, <u>y = 0</u>

The table of values is presented as follows;

\begin{array}{|c|c|c}x&f(x)\\0&200 & y-intercept\\1&210\\3&231.525\\4&243.1\\5&255.26\end{array}

4. The domain is the possible x-values which is; 0 ≤ x < ∞

The range is the possible y-values which is; 200 ≤ f(x) < ∞

Which gives;

  • Domain; [0, ∞)
  • Range: [200, ∞)

5. The population of the fish after 11 years is f(11) = 200·(1.05)¹¹

f(11) = 200 × (1.05)¹¹ ≈ 342

  • The population of the fish after 11 years is <u>346 (fishes)</u>

Learn more about exponential function here:

brainly.com/question/15662160

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<h3>Asked :</h3>
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