3 years ago

How many sets of three integers between 1 and 20 are possible if no two consecutive integers are to be in a set?

1 answer:

8 0

<span>I'm pretty sure that the solution looks like this </span> $(20-3)!(20-4)!(20-5)!...(20-19)!$ . But Also you can use this formula (r-k+1 C r). You will get 18C3.

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sashaice [31]

Answer:

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Step-by-step explanation:

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2 years ago

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Charra [1.4K]

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3 years ago

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nirvana33 [79]

Answer:

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Step-by-step explanation:

I don't even know, but yeah.

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3 years ago

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