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boyakko [2]
4 years ago
11

A store is having a sale on walnuts and chocolate chips. For 2 pounds of walnuts and 5 pounds of chocolate chips, the total cost

is 10.00. For 8 pounds of walnuts and 3 pounds of chocolate chips, the total cost is 23.00. Find the cost for each pound of walnuts and each pound of chocolat chips
Mathematics
2 answers:
oksian1 [2.3K]4 years ago
8 0
It will be $2.50 for each pound of walnuts, and it will be $1 for each pound of chocolate chips.

I know this hold true because when we multiply $2.50 by 2, we get $5, and add that to the other $5 from the chocolate chips and we will get $10. We can also multiply $2.50 by 8 and add $3 from chocolate chips to get $20 + $3, or $23.
Julli [10]4 years ago
7 0
1.  2w+5c=10
2.  8w+3c=23
Simplify the first equation: w=(10-5c)/2
Substitute: 8((10-5c)/2)+3c=23
Simplify:(80-40c)/2+3c=23
40-20c+3c=23,
17c=17, 1 pound of chocolate chips is $1
Substitute: 2w+5=10, 1 pound of walnuts is $2.50
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Step-by-step explanation:

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In the point (3,-2), what is<br> the x-value? Which<br> quadrant is this point<br> located?
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Answer:

Step-by-step explanation:

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4 0
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Answer if you have a big brain 96 POINTS
nordsb [41]

Answer:

1) 2x+7

2) -3x+11

3) 0.75x-2

4) -2x+0

5) -1.5x+2

6) -4x+16

Step-by-step explanation:

1) y = mx + c

m = 2 when x=1 , y=9

9 = 2(1)+c

c = 7

y = 2x + 7

2) m = -3

When x=4, y= -1

-1 = -3(4) + c

c = -1+12 = 11

y = -3x + 11

3) m = 0.75

When x= -4, y= -5

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-5 = -3 + c

c = -2

y = 0.75x - 2

4) m = (y2-y1)/(x2-x1)

m = (2-(-6))/(-1-3) = 8/-4 = -2

y = -2x + c

When x= -1, y= 2

2 = -2(-1) + c

2 = 2 + c

c = 0

y = -2x + 0

5) m = (-10-(-4))/(8-4)

m = (-10+4)/4 = -6/4 = -1.5

y = -1.5x + c

When x= 4, y= -4

-4 = -1.5(4) + c

-4 = -6 + c

c = 2

y = -1.5x + 2

6) m = (-4-4)/(5-3) = -8/2 = -4

When x= 3, y= 4

4 = -4(3) + c

4 = -12 + c

c = 16

y = -4x + 16

8 0
3 years ago
Read 2 more answers
A cylinder shaped can needs to be constructed to hold 400 cubic centimeters of soup. The material for the sides of the can costs
LenKa [72]

Answer:

The dimensions of the can that will minimize the cost are a Radius of 3.17cm and a Height of 12.67cm.

Step-by-step explanation:

Volume of the Cylinder=400 cm³

Volume of a Cylinder=πr²h

Therefore: πr²h=400

h=\frac{400}{\pi r^2}

Total Surface Area of a Cylinder=2πr²+2πrh

Cost of the materials for the Top and Bottom=0.06 cents per square centimeter

Cost of the materials for the sides=0.03 cents per square centimeter

Cost of the Cylinder=0.06(2πr²)+0.03(2πrh)

C=0.12πr²+0.06πrh

Recall: h=\frac{400}{\pi r^2}

Therefore:

C(r)=0.12\pi r^2+0.06 \pi r(\frac{400}{\pi r^2})

C(r)=0.12\pi r^2+\frac{24}{r}

C(r)=\frac{0.12\pi r^3+24}{r}

The minimum cost occurs when the derivative of the Cost =0.

C^{'}(r)=\frac{6\pi r^3-600}{25r^2}

6\pi r^3-600=0

6\pi r^3=600

\pi r^3=100

r^3=\frac{100}{\pi}

r^3=31.83

r=3.17 cm

Recall that:

h=\frac{400}{\pi r^2}

h=\frac{400}{\pi *3.17^2}

h=12.67cm

The dimensions of the can that will minimize the cost are a Radius of 3.17cm and a Height of 12.67cm.

3 0
3 years ago
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