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Tanzania [10]
4 years ago
13

Barb is going to cover a rectangle area 8 feet by 10 feet with rectangle paving blocks that are 4 inches by 8 inches by 2 inches

to make a flat patio. What is the minimum number of paving blocks she will need if all the paving blocks will face the same direction?
Mathematics
1 answer:
soldier1979 [14.2K]4 years ago
5 0

Step-by-step explanation:

First, transform 8 feet and 10 feet into inches so we can work with the same measurements

8 * 12 = 96 in

10 * 12 = 120 in

Next find the patio rectangle area.

96 * 120 = 11520 in^2

Now find the paving block area

4 * 8 = 32 in^2

Now, find out how many paving blocks will go into the patio rectangle area.

11520 / 32 = 360

The minimum number is 360 paving blocks

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John is playing a gamr of darts. The probability that he throws a dart into the center of the dart board (bulls eyes) is 1/10. T
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At CVS, the tax paid was $2.45, which was 7% of the cost. What was the cost of the items purch
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'Percentage' is obtained by multiplying 2.45 by - 7%.

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<h2>How do we check the result?</h2>

If - 7% × 2.45 = - 0.1715 =>

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... And see if we get as a result: - 7%.

<h2>Note:</h2>

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2 years ago
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saveliy_v [14]

5. Answer: see explanation

<u>Step-by-step explanation:</u>

If the roots are m and 3m, then x = m and x = 3m

⇒ x - m = 0    and      x - 3m = 0

⇒ (x - m)(x - 3m) = 0

⇒ x² - 4mx + 3m² = 0

Since x² + px + q = 0   then  p = -4m   and q = 3m²

3p² = 3(-4m)²               16q = 16(3m²)

      = 3(16m²)                      = 48m²

      = 48m²

3p² = 48m² = 16q     ⇒           3p² = 16q

**********************************************************************************************

6. Answer: 8 or 18

<u>Step-by-step explanation:</u>

The Area of the entire rectangle (A = L × w) is 12 × 10 = 120

The Area of the shaded region is 72, so the Area of the non-shaded region is 120 - 72 = 48.

There are two non-shaded triangles.

  • Bigger non-shaded Δ: L = 12-x, w = 10  ⇒ A = \dfrac{10(12-x)}{2}
  • Smaller non-shaded Δ: L = x, w = x ⇒ A=\dfrac{x(x)}{2}

Combine the Areas of both triangles and set it equal to the Area of the non-shaded region:

\dfrac{x(x)}{2}+\dfrac{10(12-x)}{2}=48\\\\\\\dfrac{x^2}{2}+\dfrac{120-10x}{2}=48\\\\\\\dfrac{x^2-10x+120}{2}=48\\\\\\x^2-10x+120=96\\\\x^2-10x+24=0\\\\(x-4)(x-6)=0\\\\x - 4 = 0\quad or\quad x-6=0\\x=4\qquad or\qquad x=6\\\\\text{Based on the image provided, it appears that the x-value will be the}\\\text{smallest of the two possible solutions (4), but both solutions are valid.}

Area of ΔBEF:

\text{when x = 4, A =}\ \dfrac{4(4)}{2}=\dfrac{16}{2}=8\\\\\\\text{when x = 6, A =}\ \dfrac{6(6)}{2}=\dfrac{36}{2}=18

5 0
3 years ago
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