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lbvjy [14]
3 years ago
11

The 12th term and the sim of 1+3+5+7+.....

Mathematics
1 answer:
zzz [600]3 years ago
7 0

To find this, first find the factor or rate of which the numbers are moving. To do so do as follows.

subtract 1 from 3

3-1=2

So each number is having 2 added to it.

Now add two to 7 and the numbers afterwards till you get the 12th term

7+2=9

1+3+5+7+9

9+2=11

1+3+5+7+9+11

11+2=13

1+3+5+7+9+11+13

13+2=15

1+3+5+7+9+11+13+15

15+2=17

1+3+5+7+9+11+13+15+17

17+2=19

1+3+5+7+9+11+13+15+17+19

19+2=21

1+3+5+7+9+11+13+15+17+19+21

21+2=23

1+3+5+7+9+11+13+15+17+19+21+23

So 23 is the 12th term


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The student with the correct answer is Dylan who says the decimal should be placed between the 8 and 0.

This is base on the estimation that 3.01 is a two decimal place number, so the product 18.06 should also be in 2 decimal place.

<h3>How to find product of decimal number?</h3>

A decimal number is a number expressed in the decimal system (base 10).

Place value:

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6 × 3.01

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Therefore, Lucas is incorrect with his answer that the decimal should be placed between the 1 and 8.

Read more on decimal number:

brainly.com/question/1827193

#SPJ1

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