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lbvjy [14]
3 years ago
11

The 12th term and the sim of 1+3+5+7+.....

Mathematics
1 answer:
zzz [600]3 years ago
7 0

To find this, first find the factor or rate of which the numbers are moving. To do so do as follows.

subtract 1 from 3

3-1=2

So each number is having 2 added to it.

Now add two to 7 and the numbers afterwards till you get the 12th term

7+2=9

1+3+5+7+9

9+2=11

1+3+5+7+9+11

11+2=13

1+3+5+7+9+11+13

13+2=15

1+3+5+7+9+11+13+15

15+2=17

1+3+5+7+9+11+13+15+17

17+2=19

1+3+5+7+9+11+13+15+17+19

19+2=21

1+3+5+7+9+11+13+15+17+19+21

21+2=23

1+3+5+7+9+11+13+15+17+19+21+23

So 23 is the 12th term


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About when does the softball reach its maximum height?
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Based on the given graph, the time when the softball reaches its maximum height is about 1.8 seconds.

<h3>When is the softball at it highest?</h3>

The softball is at its maximum height at the point where the curve begins to go back down.

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7 0
1 year ago
Solve the system x+3=22 2x-y=2
steposvetlana [31]

Hello from MrBillDoesMath!

Answer:

x = 19, y = 36

Discussion:

x + 3 = 22     (*)

2x - y = 2      (**)


Subtract 3 from both sides of (*)

x + 3 -3 = 22 = 3 = 19  =>

x = 19


Substitute x= 19 in (**)

2(19) - y = 2 =>

38 - y = 2 =>           (add y to both sides)

38 -y + y = 2 + y =>

38 = 2 + y  =>         (subtract 2 from both sides)

38 -2 = 2 -2 + y =>

36 = y


Regards,  

MrB

P.S.  I'll be on vacation from Friday, Dec 22 to Jan 2, 2019. Have a Great New Year!


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