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ch4aika [34]
2 years ago
14

At which x-value does the cosine function attain a maximum value?.

Mathematics
1 answer:
Troyanec [42]2 years ago
3 0

Answer:

cos(x) = ???

so the maximum cosine can be is 1 and that happens when x = 0

I'm pretty sure that's what you meant...

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The numbers of blue, red, green and black pencils are proportional to the numbers 2, 3, 5, and 7, respectively. If we add the nu
Vitek1552 [10]

Answer:

  20 green pencils

Step-by-step explanation:

The difference between black and green "ratio units" is 7 -5 = 2. The difference between red and blue ratio units is 3 -2 = 1. The sum of those differences is 2 +1 = 3 ratio units, which represent 12 pencils. Then each ratio unit represents 12/3 = 4 pencils.

The 5 ratio units of green pencils represent 5·4 pencils = 20 green pencils.

_____

If you need an equation, you can use k as the constant of proportionality. Then the sum of differences described is ...

  (7k -5k) + (3k -2k) = 12

  3k = 12 . . . . simplify

  k = 4 . . . . . . divide by 3

  5k = 5·4 = 20 . . . . . number of green pencils

6 0
3 years ago
Read 2 more answers
A contractor digs a hole for the basements of a new house that is 40 feet long and 10 1/2 feet deep. What is the width of the ho
34kurt
D. 15.5

40*10.5 = 420

6510/420 = 15.5
7 0
3 years ago
Andrew McCutchen hit 18 homeruns in 9 baseball games. At this rate, how many homeruns will he have hit
Feliz [49]

Answer:

if it's 18 home runs in 9 baseball games

then you're dividing 18 by 9 which is 2 home runs for every 9 baseball games

to prove if you're right (9×2=18)

if it's 11 baseball games then 11×2=22

Hope It Helps ☺️

6 0
3 years ago
Differentiate the following functions (x^3+1)(x-2)÷x^2​
Masja [62]

Given:

The given function is:

\dfrac{(x^3+1)(x-2)}{x^2}

To find:

The differentiation of the given function.

Solution:

Consider the given function,

y=\dfrac{(x^3+1)(x-2)}{x^2}

It can be written as:

y=\dfrac{(x^3)(x)+(x^3)(-2)+(1)(x)+(1)(-2)}{x^2}

y=\dfrac{x^4-2x^3+x-2}{x^2}

y=\dfrac{x^4}{x^2}-\dfrac{2x^3}{x^2}+\dfrac{x}{x^2}-\dfrac{2}{x^2}

y=x^2-2x+\dfrac{1}{x}-\dfrac{2}{x^2}

Differentiate with respect to x.

y'=\dfrac{d}{dx}(x^2)-\dfrac{d}{dx}(2x)+\dfrac{d}{dx}(x^{-1})-\dfrac{d}{dx}\2(x^{-2})

y'=2x-2(1)+(-x^{-2})-2(-2x^{-3})

y'=2x-2-\dfrac{1}{x^2}+\dfrac{4}{x^3}  

Therefore, the differentiation of the given function is 2x-2-\dfrac{1}{x^2}+\dfrac{4}{x^3}.

8 0
3 years ago
Find the reciprocal of - c​
labwork [276]

Answer:

The reciprocal of X is defined as 1/X,

Step-by-step explanation:

idk tbh

7 0
3 years ago
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