All categories

3 years ago

Solve each inequality. Graph and check the solution.

1 answer:

4 0

Just divide and multiply BUT when you divide or multiply by negative numbers you switch the symbol.

#1 is -18÷-3= 6; x is less than 6
#2 is 4×-2= -8; y is less than -8
#3 I don't understand the question
#4 -1.5×-2= 3; c is less than 3
#5 is 1/20×-5= -0.25; x is less than -0.25
#6 is not possible
#7 is 3÷-2=-1.5; b is greater than -1.5
#8 is -70÷-0.5= 35; a is greater than 35

Tbh I don't think any of these are right but I tried and it took me awhile so :/

You might be interested in

ra1l [238]

Answer:

average speed of sprinter will be 10.42m/s

Step-by-step explanation:

distance covered=s=100m

time taken=t=9.67m/s

average speed=10.42m/s

5 0

3 years ago

Find the size of the angle c !!

Vinil7 [7]

Answer:

a= 31

b=92

c=44

Step-by-step explanation:

8 0

3 years ago

A turtle walks 5/8 of a mile in 50 minutes. How many minutes will it take for the turtle to walk 1 mile? ANSWER ASAP!!!!

Vlad1618 [11]

I'm pretty sure the answer would be 80 minutes

7 0

3 years ago

Read 2 more answers

Five cards are dealt from a standard 52-card deck. (a) What is the probability that we draw 1 ace, 1 two, 1 three, 1 four, and 1

labwork [276]

Answer:

Step-by-step explanation:

As there are total 52 cards in a deck and we have to draw a set of 5 cards, we can use the formula of combination to find the total number of possible ways of drawing 5 cards.

Number of ways to draw 5 cards = $N_T$

$N_T\;=\;({}^NC_k)\\\\N_T\;=\;({}^{52}C_5)\\\\N_T\;=\;2,598,960$

(a) Assuming the cards are drawn in order (would not affect the probability). The of getting Ace, 2, 3, 4 and 5 can be obtained by multiplying the probability of getting cards below 6 (20/52) with the probability of getting 5 different cards (4 choices for each card).

$P(a)\;=\;\frac{20}{52}*\frac{4}{52}*\frac{4}{51}*\frac{4}{50}*\frac{4}{49}*\frac{4}{48}\\\\P(a)\;=\; 1.3133*10^{-6}$

(b) For a straight we require our set to be in a sequence. The choices for lowest value card to produce a sequence are ace, 2, 3, 4, 5, 6, 7, 8, 9, or 10. Hence, the number of ways are $({}^{10}C_1)$ .

For each card we can draw from any of the 4 sets. It can be described mathematically as: $({}^{4}C_1)*({}^{4}C_1)*({}^{4}C_1)*({}^{4}C_1)*({}^{4}C_1)\;=\;[({}^{4}C_1)^5]$

Therefore, the total outcomes for drawing straight are:

$N_S\;=\;({}^{4}C_1)*({}^{4}C_1)^5\;=\;10240$

Thus, the probability of getting a straight hand is:

$P(b)\;=\;\frac{N_S}{N_T}\\\\P(b)\;=\;\frac{10240}{2598960}\\\\P(b)\;=\; 0.0039$

7 0

3 years ago

ANSWER FOR 10 POINTS!<br> THANKS

Roman55 [17]

The diagonal line is the hypotenuse of a triangle whose sides are both 50 yds, so you can use Pythagoras (a^2 + b^2 = c^2) to find the answer. 50 × 50 = 2500, and 2500 + 2500 = 5000. Because 5000 is c^2, the answer is D) √5000. I hope this helps!

8 0

4 years ago