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algol13
2 years ago
15

HELP ASAP!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
Nadusha1986 [10]2 years ago
8 0

Answer:

#3 2 Right, 4 Down & #4 Vertical Compression

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Pls help!! Find the volume of the flower vase. Round to the nearest tenth.
Contact [7]

Answer:

Volume = 1596.2 cubic cm

Step-by-step explanation:

Volume = volume of box - volume of cylinder

Volume = (LxWxH) - 1/3 (pi * r^2 *h)

Volume = (10 x 12 x 20) -1/3 (3.14 x 8^2 x 12)

Volume = 2400 - 803.8

Volume = 1596.2 cm^3

3 0
3 years ago
How to solve this one​
ladessa [460]

A dotted line is not included in the solution so there is no equal sign.

The blue area is to the right of the dotted line so the solution is >

The line crosses the x axis at -2

The answer is : x-y > -2

4 0
2 years ago
Martina chose a random sample of 10 bags of candy from two different Brands, A and B. All bags in the sample are the same size.
Alborosie
I found the dot plots that accompanies this problem.

Based on the plots, the <span>statement that gives is a valid comparison of the number of candies in the bags of the two Brands is:

</span><span>B. The number of candies in the bags from Brand B is greater and less consistent than the number of candies in the bags from Brand A.

Dots in Brand B are scattered and whereas dots in Brand A are not and they are more concentrated between 52 to 55 range. </span>

7 0
2 years ago
Comparing Leaking Pool Problem
Blababa [14]

Answer:

<em>Pool 1 leaks faster than pool 2.</em>

Step-by-step explanation:

<u>Rates of change</u>

The rate of change (ROC) is a measure that compares two quantities, usually to know how fast one variable changes in time.

We are given two rates of change for two pools that are leaking. The first one loses 2/3 gallon in 15 minutes, and the other loses 3/4 gallon in 20 minutes.

To compare them, we are required to express time in hours. Recall one hour has 60 minutes, or equivalently, one minute has 1/60 hours. Converting both times, we have:

15 minutes = 15/60 = 1/4 hours

20 minutes = 20/60 = 1/3 hours

Now compute both rates of change:

Pool 1:

\displaystyle ROC_1=\frac{2/3}{1/4}=\frac{8}{3}\approx 2.67\ gal/h

Pool 2:

\displaystyle ROC_2=\frac{3/4}{1/3}=\frac{9}{4}= 2.25\ gal/h

Comparing both ratios, it's clear pool 1 leaks faster than pool 2.

8 0
3 years ago
Can someone help me with this? I'm really confused. Im supposed to be doing a projet, but i don't know how to do it
mr_godi [17]

Answer:

Step-by-step explanation:

the image isnt showing

5 0
2 years ago
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