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3 years ago

The largest mass extinction in Earth's history occurred at the end of which era? A. Paleozoic B. Mesozoic C. Permian D. Triassic

Mathematics

1 answer:

VashaNatasha [74]3 years ago

3 0

Hi,

Answer: A) Paleozoic

<u>My work:</u> Dinosaurs died approximately 66 million years ago. The era was Paleozoic.

I Hope I Helped!

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IXL geometry please help!

Sedaia [141]

<h3>Answer: 32 degrees</h3>

================================

Work Shown:

Inscribed angle theorem

arc measure = 2*(inscribed angle)

arc ABC = 2*(angle D)

arc ABC = 2*(35)

arc ABC = 70 degrees

-------------

break arc ABC into its smaller pieces

(minor arc AB)+(minor arc BC) = arc ABC

(38)+(minor arc BC) = 70

minor arc BC = 70-38

minor arc BC = 32

8 0

3 years ago

If m∠3 = 110°, find m∠2: <br><br> A. 70°<br> B. 90°<br> C. 110°<br> D. 120°

stiv31 [10]

A. 70°

Supplementary angles always = 180°

Where 180 - 110 = 70

110+ 70 = 180

7 0

2 years ago

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What is the equation of the line that passes through (0, -2) and has a slope of 0?

11Alexandr11 [23.1K]

Answer:

y = -2

Step-by-step explanation:

The horizontal line through this point has a slop of 0

8 0

2 years ago

Identify the type of function represented by

SCORPION-xisa [38]

That's definitely an example of exponential decay, since the base (1/2) (also called the "common ratio") is greater than 0 but less than 1.

6 0

3 years ago

Which of the following expressions is equivalent to a3 + b3?

lubasha [3.4K]

ANSWER
${a}^{3} + {b}^{3} = (a + b)( {a}^{2 } - ab + {b}^{2} )$

EXPLANATION

To find the expression that is equivalent to
${a}^{3} + {b}^{3}$
we must first expand
${(a + b)}^{3}$
Then we rearrange to find the required expression.

So let's get started.

${(a + b)}^{3} = (a + b) {(a + b)}^{2}$

We expand the parenthesis on the right hand side to get,

${(a + b)}^{3} = (a + b) ( {a}^{2} + 2ab + {b}^{2} )$

We expand again to obtain,

${(a + b)}^{3} = {a}^{3} + 3 {a}^{2}b + 3a {b}^{2} + {b}^{3}$

Let us group the cubed terms on the right hand side to get,

${(a + b)}^{3} = {a}^{3} + {b}^{3} + 3 {a}^{2}b + 3a {b}^{2}$

${(a + b)}^{3} = {a}^{3} + {b}^{3} + 3ab (a+ b)$

We make the cubed terms the subject,

${(a + b)}^{3} - 3ab (a+ b) = {a}^{3} + {b}^{3}$

We factor to get,

$(a + b)({(a + b)}^{2} - 3ab ) = {a}^{3} + {b}^{3}$

We expand the bracket on the left hand side to get,

$(a + b)( {a}^{2} + 2ab + {b}^{2} - 3ab ) = {a}^{3} + {b}^{3}$

We finally simplify to get,

$(a + b)( {a}^{2} - ab + {b}^{2} ) = {a}^{3} + {b}^{3}$

5 0

3 years ago

Read 2 more answers