The distance between two cities is
75
k
m
s
.
Explanation:
As a road of
4
c
m
.
on road map indicates a road of length equal to
30
k
m
.
Each
c
m
.
on map indicates
30
4
=
7.5
k
m
s
.
Hence a distance of
10
c
m
.
between two cities on the map indicates
7.5
×
10
=
75
k
m
s
Answer:
-30
Step-by-step explanation:
-|-30-(10-20)|-|5-(10-15)|=-|-30-(-10)|-|5-(-5)|
=-|-30+10|-|5+5|
=-|-20|-|10|
=-(20)-(10)
= -20-10
= -30
Answer:
Yes you are correct
Step-by-step explanation:
Answer:
C) 6 feet
Step-by-step explanation:
The diagram is shown in the attachment.
Using the Pythagoras Theorem,
![x^2=4^2+4^2](https://tex.z-dn.net/?f=x%5E2%3D4%5E2%2B4%5E2)
![x^2=16+16](https://tex.z-dn.net/?f=x%5E2%3D16%2B16)
![x^2=32](https://tex.z-dn.net/?f=x%5E2%3D32)
We take positive square root to obtain
![x=\sqrt{32}](https://tex.z-dn.net/?f=x%3D%5Csqrt%7B32%7D)
![x=4\sqrt{2}](https://tex.z-dn.net/?f=x%3D4%5Csqrt%7B2%7D)
x=5.66ft
Rounding to the nearest feet we have x=6ft
To find the number of years between 1844 to 2015 you have to subtract.
Lets say that x is the # of years in between 1844 and 2015
Then we have:
![\sf{2015 - 1844 =x}](https://tex.z-dn.net/?f=%5Csf%7B2015%20-%201844%20%3Dx%7D)
After doing the subtraction using a calculator or a pencil and paper, you get that:
![\huge{\boxed{\bf{x=171}}}](https://tex.z-dn.net/?f=%5Chuge%7B%5Cboxed%7B%5Cbf%7Bx%3D171%7D%7D%7D)
So 171 years have passed from 1844 to reach to 2015.