Answer:
286cm²
Step-by-step explanation:
Let the parallel sides be 12cm and 10cm
Height h = 26cm
Area of a trapezium = 1/2(a+b) * h
Area of a trapezium = 1/2(12+10)* 26
Area of a trapezium = 1/2(22)*26
Area of a trapezium = 11 * 26
Area of a trapezium = 286cm²
Hence the area of the tiles is 286cm²
Answer:
f(2) = 729
Step-by-step explanation:
f(x) = 3^(x + 4)
Let x =2
f(2) = 3^(2 + 4)
f(2) = 3^(6)
f(2) = 729
The area enclosed by the figure is 4533.48 square meters.
<u>Step-by-step explanation:</u>
Side length of the square = 42m
The semicircle is attached to each side of the square. So the diameter of the semicircle is the length of the square.
Radius of the semicircle = 21m
Area of the square = 42 x 42 = 1764 square meters
Area of 1 semicircle = π(21 x 21) /2
= (3.14) (441) /2
= 1384.74/2
= 692.37 square meters
Area of 4 semicircle = 4 x 692.37
= 2769.48 square meters
Total area = 1764 + 2769.48
= 4533.48 square meters
The area enclosed by the figure is 4533.48 square meters.
To find the relation between them, you need transform them to the same currency. Let's transform them to cents.
$3.60 = 360 cents.
One quarter is 25 cents, and one nickel is 5 cents.
So 360 = 25q + 5n
Hope this helps! :D
