3 years ago

How do I solve x^2+y^2=41 y=4x-11

Mathematics

1 answer:

Paul [167]3 years ago

3 0

Download photomath on your phone and it will solve it for you and give you answer too

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4 years ago

Read 2 more answers

At what point do the curves r1(t) = t, 5 − t, 48 t2 and r2(s) = 8 − s, s − 3, s2 intersect?

DerKrebs [107]

Set components equal:
$t = 8-s \\ 5-t = s-3 \\ 48 t^2 = s^2$

From this we find:
$t = 8-s \\ s = 4 \sqrt{3} t$

Substitute and solve system:
$t = \frac{8}{1+4 \sqrt{3}} = 1.009 \\ \\ s = 8-t = 8 - 1.009 = 6.991$

The point where they intersect is:
$(1.009, 5-1.009, 48(1.009)^2)$