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pav-90 [236]
3 years ago
9

2 divided by 3 + 4 times 2

Mathematics
2 answers:
Stells [14]3 years ago
5 0

Answer:

8.66666666666 (11)

Step-by-step explanation:

2 divided by 3 -.666666666666666

4 times 3 is 8

Alja [10]3 years ago
4 0

Answer:

8 2/3

Step-by-step explanation:

2/3+4·2=???

2/3+8=???

2/3+8= 8 2/3

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Y=(x+9)÷(x-3)<br>Find the value of y when x=5​
torisob [31]

Answer:

7

Step-by-step explanation:

Simply plug in 5 for <em>x</em>

y = (5 + 9)/(5 - 3)

y = 14/2

y = 7

7 0
4 years ago
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If p and q vary inversely and p is 10 when q is 19 , determine q when p is equal to 2
GenaCL600 [577]
You divide 10 by 5 is two so 19 decided by five is 3.8
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(9) There are 18 elephants in a herd. The number of adult elephants is two times the number of young elephants in the herd. How
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12 adult elephants, 6 young elephants = 18 total :)
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3 years ago
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A certain bowler can bowl a strike 85 % of the time. What is the probability that she ​a) goes three consecutive frames without
Artist 52 [7]

Answer:

a) 0.34% probability that she goes three consecutive frames without a​ strike.

b) 1.91% probability that she her first strike in the third ​frame

c) 99.66% probability that she has at least one strike in the first three ​frames.

d) 14.22% probability that she bowls a perfect game.

Step-by-step explanation:

For each frame, there are only two possible outcomes. Either there is a strike, or there is not. The probability of a strike happening in a frame is independent of other frames. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

A certain bowler can bowl a strike 85 % of the time.

This means that p = 0.85

a) goes three consecutive frames without a​ strike?

This is P(X = 0) when n = 3. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{3,0}.(0.85)^{0}.(0.15)^{3} = 0.0034

0.34% probability that she goes three consecutive frames without a​ strike.

​b) makes her first strike in the third ​frame?

No strike during the first two(with a 15% probability)

Strike during the third(85% probability). So

P = 0.15*0.15*0.85 = 0.0191

1.91% probability that she her first strike in the third ​frame

c) has at least one strike in the first three ​frames? ​

Either there are no strikes, or there is at least one strike. The sum of the probabilities of these events is 100%.

From a), 0.34% probability that she goes three consecutive frames without a​ strike.

100 - 0.34 = 99.66

99.66% probability that she has at least one strike in the first three ​frames.

d) bowls a perfect game​ (12 consecutive​ strikes)?

This is P(X = 12) when n = 12. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 12) = C_{12,12}.(0.85)^{12}.(0.15)^{0} = 0.1422

14.22% probability that she bowls a perfect game.

3 0
4 years ago
Which situation describes a time when it would be all right to round the numbers?
Alborosie
I think the correct answer is B
6 0
3 years ago
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