Answer:
The probability is 0.0052
Step-by-step explanation:
Let's call A the event that the four cards are aces, B the event that at least three are aces. So, the probability P(A/B) that all four are aces given that at least three are aces is calculated as:
P(A/B) = P(A∩B)/P(B)
The probability P(B) that at least three are aces is the sum of the following probabilities:
- The four card are aces: This is one hand from the 270,725 differents sets of four cards, so the probability is 1/270,725
- There are exactly 3 aces: we need to calculated how many hands have exactly 3 aces, so we are going to calculate de number of combinations or ways in which we can select k elements from a group of n elements. This can be calculated as:

So, the number of ways to select exactly 3 aces is:

Because we are going to select 3 aces from the 4 in the poker deck and we are going to select 1 card from the 48 that aren't aces. So the probability in this case is 192/270,725
Then, the probability P(B) that at least three are aces is:

On the other hand the probability P(A∩B) that the four cards are aces and at least three are aces is equal to the probability that the four card are aces, so:
P(A∩B) = 1/270,725
Finally, the probability P(A/B) that all four are aces given that at least three are aces is:

I believe it would be dilated by 3/4
If you think of a rectangle, let’s say it is 8 by 4, the perimeter of this rectangle would be 24.
Now if you dilate the side values, you get 6 by 3 and the perimeter equals 18
So you then get 18/24 which is equal to 3/4
Hope this is right and makes sense! Have a good day!
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2+(1/2) +34- (1/10)
2.5 + 34 - .1
36.5-.1
36.4
I'm not 100% sure what this all means because I'm in a different school but, I believe they have a side length of 4600.
P.S. If it doesn't work, I am so sorry
The answer would be log base 2 of 6 over log base 2 of 3