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dsp73
3 years ago
11

ifying an Error Examine the work shown. Explain the error and find the correct result. 2(4 – 16) – (–30) 2(–12) – (–30) 24 – (–3

0) 54
Mathematics
3 answers:
Dvinal [7]3 years ago
7 0

Answer:

The error is in the middle: 2(-12) = -24 not 24.

Step-by-step explanation:

katen-ka-za [31]3 years ago
6 0
2(-12)= -24 not 24 so that would be the error
SmartyPants2 years ago
0 0

The product of two numbers with different signs is negative, so 2(-12) = -24, not 24. Then -24 — (-30) = -24 + 30 = 6.

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Under extreme driving conditions, such as off-roading, car owners are supposed to have the oil changed in their car every 1,000
sladkih [1.3K]

Answer: Off-road can cause more problems for the car than street driving

Step-by-step explanation:

In the above argument, the fact that extreme driving condition is used for off-road denotes the reason why it supposedly leads to a possible more damage to the car. There is however, a general habit that the car owners do not practise the regular oil change until their yearly maintenance, using the car off-road without the necessary preventive maintenance leads to more damages to the car during the yearly maintenance. This makes the answer to be "Off-road can cause more problem to the car than street driving".

8 0
3 years ago
Which of the following are point-slope equations of the line going through (-3, -5) and (2, 4)? Check all that apply. *Marking B
andreyandreev [35.5K]

Answer:

A B D F are correct answers.

4 0
3 years ago
2. Suppose 27 blackberry plants started growing in a yard. Absent constraint, the blackberry plants will spread by 80% a month.
Marta_Voda [28]

Explanation

The question indicates we should use a logistic model to estimate the number of plants after 5 months.

This can be done using the formula below;

\begin{gathered} P(t)=\frac{K}{1+Ae^{-kt}};A=\frac{K-P_{0_{}}}{P_0}_{} \\ \text{From the question} \\ P_0=\text{ Initial Plants=27} \\ K=\text{Carrying capacity =140} \end{gathered}

Workings

Step 1: We would need to get the value of A using the carrying capacity and initial plants that started growing in the yard.

This gives;

\begin{gathered} A=\frac{140-27}{27} \\ A=\frac{113}{27} \end{gathered}

Step 2: Substitute the value of A into the formula.

P(t)=\frac{140}{1+\frac{113}{27}e^{-kt}}

Step 3: Find the value of the constant k

Kindly recall that we are told that the plants increase by 80% after each month. Therefore, after one month we would have;

\begin{gathered} P(1)=27+(\frac{80}{100}\times27) \\ P(1)=\frac{243}{5} \end{gathered}

We can then have that after t= 1month

\begin{gathered} \frac{140}{1+\frac{113}{27}e^{-k\times1}}=\frac{243}{5} \\ Flip\text{ the equation} \\ \frac{1+\frac{113}{27}e^{-k}}{140}=\frac{5}{243} \\ 243(1+\frac{113}{27}e^{-k})=700 \\ 243+1017e^{-k}=700 \\ 1017e^{-k}=700-243 \\ 1017e^{-k}=457 \\ e^{-k}=\frac{457}{1017} \\ -k=\ln (\frac{457}{1017}) \end{gathered}

Step 4: Substitute -k back into the initial formula.

\begin{gathered} P(t)=\frac{140}{1+\frac{113}{27}e^{\ln (\frac{457}{1017})t}} \\ =\frac{140}{1+\frac{113}{27}(e^{\ln (\frac{457}{1017})})^t} \\ P(t)=\frac{140}{1+\frac{113}{27}(\frac{457}{1017}^{})^t} \\  \end{gathered}

The above model is can be used to find the population at any time in the future.

Therefore after 5 months, we can estimate the model to be;

\begin{gathered} P(5)=\frac{140}{1+\frac{113}{27}(\frac{457}{1017}^{})^5} \\ P(5)=\frac{140}{1.07668} \\ P(5)=130.029\approx130 \end{gathered}

Answer: The estimated number of plants after 5 months is 130 plants.

8 0
1 year ago
1,985 + 12,000 + what ? = 14,471 .
Scrat [10]

Answer:

486

Step-by-step explanation:

1,985 + 12,000 + x = 14,471

x = 14471 - 12000 - 1985

x = 486

6 0
3 years ago
Read 2 more answers
I need help 1-3 please help I’ll give brainliest
8_murik_8 [283]
1. To represent a function all inputs need to only have ONE output. The inputs are the x values and the outputs are the y values. So, your answer would be all of the except the last 3.
6 0
3 years ago
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