Rectangle ABCD is dilated to create rectangle A'B'C'D'. The width of

Mathematics

1 answer:

Slav-nsk [51]3 years ago

8 0

i just took the quiz and its 32 :)

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What is the y intercept for the equation –2x + 5 = –10?

Simora [160]

There is no y-intercept.

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3 years ago

Let v1=(3,5) and v2=(-4,7).

Nat2105 [25]

PART A

The given vectors are,

$v_1 = \: < \: 3 , \: 5 \: >$

$v_2 = \: < \: - 4 , \: 7 \: >$

The magnitude of the vector

$v= \: < \: x , \: y \: > \:$

is given by:

$|v| = \sqrt{ {x}^{2} + {y}^{2} }$

This implies that,

$|v_1| = \sqrt{ {3}^{2} + {5}^{2} }$

$|v_1| = \sqrt{9 + 25}$

$|v_1| = \sqrt{34}$

$|v_2| = \sqrt{ {( - 4)}^{2} + {7}^{2} }$

$|v_2| = \sqrt{ 16+ 49}$

$|v_2| = \sqrt{65}$

PART B

To find the unit vector in the direction of a given vector, we divide by the magnitude of that vector.

$^{ - } _{v_1} = \: < \: \frac{3}{ \sqrt{34} } , \: \frac{5}{ \sqrt{34} } \: >$

Rationalize the denominator.

$^{ - } _{v_1} = \: < \: \frac{3\sqrt{34}}{ 34 } , \: \frac{5\sqrt{34}}{ 34 } \: >$

Also,

$^{ - } _{v_2} = \: < \: \frac{ - 4}{ \sqrt{65} } , \: \frac{7}{ \sqrt{65} } \: >$

$^{ - } _{v_2} = \: < \: \frac{ - 4\sqrt{65}}{ 65 } , \: \frac{7\sqrt{65}}{ 65 } \: >$

PART C

The sketch of the given vectors as well as their unit vectors are shown in the attachment.

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3 years ago

A triangle has an area of 16 square feet.The height is 8 feet. What is the length of the base

arsen [322]

4 is the base because the formula for a triangle is base times height divided by two, you would know that 8 times 4 would equal 32. When divided by 2 it would equal 16 which is the area. So 4 is the answer.

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3 years ago

Read 2 more answers

Conduct a Pareto analysis for the number of minutes that flights are late in the accompanying data. Interpret the results. LOADI

Paraphin [41]

Answer:

Following are the solution to the given question:

Step-by-step explanation:

Please find the attached file for the solution:

20% of flights accounted for nearly 70 to 80% of delayed minutes.