How do you graph y=(x+2)^2+5 and find the vertex, the equation for the axis of symmetry and two other points on the graph with t
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Answer:
the origin
Step-by-step explanation:
Both terms are of odd degree, so the function is an odd function. It is symmetrical with respect to the origin.
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If you recast this as y = f(x), then ...
f(x) = x^(3/5)
When we look at f(-x), we find ...
f(-x) = ((-x)^3)^(1/5) = -(x^3)^(1/5) = -(x^(3/5)) = -f(x)
An odd root of a number has the same sign as the number.
When f(-x) = -f(x), the function is odd and symmetrical about the origin.
