The sum of complementary angles is 90 degrees, thus
3x + 6 + 3x + 18 = 90
=> 6x + 24 = 90
=> 6x = 90 - 24 = 66
=> x = 66 / 6 = 11
=> m<A = 3(11) + 6 = 33 + 6 = 39 degrees.
111.1 is the answer to the question
Answer:
Option 3. 71 ft. is the distance between B and top of the hill.
Step-by-step explanation:
Let the height of the hill is h ft and the distance of A from the hill be x ft and distance from B to hill is y.
It is given distance between A and B is 45 ft. ∠BAO = 65° and ∠ABO = 80°.
We have to find the distance of B from the top of the hill.
Now from ΔACO 

From ΔBCO 
h = 5.67x
Now h = 5.67x = 2.14(45-x)
5.67x = 96.3 - 2.14x
2.14x + 5.67x = 96.3
7.81x = 96.3
x = 96.3/7.81 = 12.33 ft
Therefore 


Therefore 71 ft is the distance between B and the top of the hill.
Answer:
(a) 3 - 2x - 2x² (b) -21
Step-by-step explanation:
given, y +2x² = 3 -2x
make y the subject:
y = 3 - 2x - 2x²
if y = f(x)
then
f(x) = 3 - 2x - 2x²
(b)<u> to find f(3) we need to replace x with 3:</u>
<u />
3 - 2(3) - 2*(3)²
-21
Start your dot on 3 on the y axis. Move is downwards on the y axis by 5 everytime you move over once on the x axis. Shade all the stuff above the line since it says y is greater than -5x+3