From the given figure, we know that:
![\begin{gathered} NO\cong LO \\ NM\cong LM \\ MO\cong MO \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20NO%5Ccong%20LO%20%5C%5C%20NM%5Ccong%20LM%20%5C%5C%20MO%5Ccong%20MO%20%5Cend%7Bgathered%7D)
This means that the three sides of triangle MNO are congruent to three sides of triangle LMO. Therefore, the triangles are congruent by Side Side Side postulate.
-9-(-12)=-9+12=3
-9-12=-9+(-12)=-21
|2x - 5| - 2 = 3 |add 2 to both sides
|2x - 5| = 5 ⇔ 2x - 5 = 5 or 2x - 5 = -5 |add 5 to both sides
2x = 10 or 2x = 0 |divide both sides by 2
x = 5 or x = 0
Answer:
y -6 = 1/3(x +3) or y = 1/3x +7
Step-by-step explanation:
The slope of the line describing the given path is the x-coefficient, -3. The slope of the perpendicular line will be the negative reciprocal of that:
m = -1/(-3) = 1/3
The point-slope form of the equation for a line can be used to write the equation for the new path:
y -k = m(x -h) . . . . . line with slope m through point (h, k)
For m=1/3 and (h, k) = (-3, 6), the new path can be represented by ...
y -6 = 1/3(x +3) . . . . point-slope form
y = (1/3)x +7 . . . . . . slope-intercept form
Answer:
Is this a question. If so I will change my answer
Step-by-step explanation: