Please select the best answer from the choices provided

Firlakuza [10]

Answer:

5/2 x 1/2

Step-by-step explanation:

when you multiply fractions you multiply trait across meaning you do 5*1 and 2*2 which leaves you with 5/4 and that is equivalent to 1 &1/4

5 0

3 years ago

Plz help me fast again thanks

zimovet [89]

The answer is (d) first you solve 3/4

6 0

2 years ago

The price has changed from $120 to $75. by how many percent did it change?

galina1969 [7]

The answer would be -37.5

6 0

2 years ago

A satellite is orbiting the Earth at the rate of 25 kilometers per minute. How far will it travel in two hours?

Dvinal [7]

1 hour=60 minutes so 25*120=3000 kilometers

3 0

2 years ago

Read 2 more answers

Let X be the number of material anomalies occurring in a particular region of an aircraft gas-turbine disk. The article "Methodo

Alinara [238K]

Answer:

a) $P(X \leq 4) = 0.6289$

$P(X < 4) = 0.4335$

b) $P(4 \leq X \leq 8) = 0.5452$

c) $P(X \geq 8) = 0.0511$

d) 0.2605

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given time interval.

It is important to know that the variance has the same value as the mean in a Poisson distribution. The standard deviation is the square root of the variance.

In this problem, we have that:

$\mu = 4, \sigma = \sqrt{4} = 2$ .

To help our solution, i am going to find each of P(X = x) from x = 0 to 8[/tex]

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-4}*4^{0}}{(0)!} = 0.0183$

$P(X = 1) = \frac{e^{-4}*4^{1}}{(1)!} = 0.0733$

$P(X = 2) = \frac{e^{-4}*4^{2}}{(2)!} = 0.1465$

$P(X = 3) = \frac{e^{-4}*4^{3}}{(3)!} = 0.1954$

$P(X = 4) = \frac{e^{-4}*4^{4}}{(4)!} = 0.1954$

$P(X = 5) = \frac{e^{-4}*4^{5}}{(5)!} = 0.1563$

$P(X = 6) = \frac{e^{-4}*4^{6}}{(6)!} = 0.1042$

$P(X = 7) = \frac{e^{-4}*4^{7}}{(7)!} = 0.0595$

$P(X = 8) = \frac{e^{-4}*4^{8}}{(8)!} = 0.0298$

(a) Compute both P(X ≤ 4) and P(X < 4)

$P(X \leq 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.0183 + 0.0733 + 0.1465 + 0.1954 + 0.1954 = 0.6289$

---------

$P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.0183 + 0.0733 + 0.1465 + 0.1954 = 0.4335$

(b) Compute P(4 ≤ X ≤ 8).

$P(4 \leq X \leq 8) = P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8) = 0.1954 + 0.1563 + 0.1042 + 0.0595 + 0.0298 = 0.5452$

(c) Compute P(8 ≤ X)

That is $P(X \geq 8)$ .

The sum of the probabilities must be 1 in decimal. Either X is greater or equal to 8, or X is lesser than 8.

So

$P(X < 8) + P(X \geq 8) = 1$

$P(X \geq 8) = 1 - P(X < 8)$

From what we have in a) and b)

$P(X < 8) = P(X < 4) + P(4 \leq X < 8) = 0.4335 + 0.1954 + 0.1563 + 0.1042 + 0.0595 = 0.9489$

So

$P(X \geq 8) = 1 - P(X < 8) = 1 - 0.9489 = 0.0511$

(d) What is the probability that the number of anomalies exceeds its mean value by no more than one standard deviation

One standard deviation is 2, and the mean is 4. So, this is:

$P(4 < X \leq 6) = P(X = 5) + P(X = 6) = 0.1563 + 0.1042 = 0.2605$

6 0

3 years ago

Please select the best answer from the choices provided​

Please select the best answer from the choices provided