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Artemon [7]
4 years ago
12

What ratio is not equivalent to 24 36 a is 3/4 b is 12/18 c is 48/72 d is 4/6

Mathematics
1 answer:
pogonyaev4 years ago
3 0
If you would like to know what ratio is not equivalent to 24/36, you can calculate this using the following steps:

a. 3/4
b. 12/18 = 12*2/18*2 = 24/36
c. 48/72 = 48/2/72/2 = 24/36
d. 4/6 = 4*6/6*6 = 24/36

The correct result would be a. 3/4.
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IF YOU ANSWER RIGHT I MIGHT GIVE BRAINLIST!!!
Pie

Answer:

1. Positive, 1+2=3

2. Negative, -1-2=-3

Step-by-step explanation:

If you look at both in a graphing perspective, the point (1,2) is in Quadrant I. likewise, adding 2 to the x-coordinate will also result in the point (3,2), also in Quadrant I, where the x coordinate is positive. The point (-1,2) is in Quadrant II, and adding -2 to the x coordinate keeps it in Quadrant II, where the x-coordinate is negative.

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3 years ago
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What is the value of 2 ^ 3
Setler79 [48]

Answer:

8

Step-by-step explanation:

2^3 is the same as 2 x 2 x 2

2 x 2 is 4 and 4 x 2 is 8

so 2^3 is 8

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3 years ago
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If there are 13 inches of snow in 8 hours how many inches in are there 1 hour
Ugo [173]

Here is 3 different ways to write how much snow fell in one hour

  1. Exact form (improper fraction) form: 13/8
  2. Decimal form: 1.625
  3. Mixed number form: 1 5/8

All u need to do is divide 13 by 8

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3 years ago
Can any kind soul help me ASAP!​
CaHeK987 [17]

Answer:

Hope it helps u

Step-by-step explanation:

As we know that ,

Mean = sum of the terms/ numbers of terms

But here grouped data is given so , we use the formula

Mean=∑[f. m]/ ∑f

where f is frequency and m is mid point of each height ,

Now first we have to find the mid point of each interval, where

midpoint of each interval = (lower boundary + upper boundary)/2

m1=(150+154)/2 = 152

m2=(155+159)/2= 157,now found other by same formula, for each interval

m3= 162

m4= 167

m5=172    Now we find the midpoint of each interval ,so now

∑[f. m]=f1*m1+f2*m2+f3*m3+f4*m4+f5*m5

now putting the values of each frequency for given interval and midpoint of each interval we will get,

∑[f. m]=456+942+1296+167*x+344 = 167*x+3038

Now find,

∑f=f1+f2+f3+f4+f5

∑f=19+x

Now we have,

∑[f. m]=167*x+3038

∑f=19+x

also given mean height=161.6 cm

putt these values in above equation we get,

161.6=\frac{167*x+3038}{19+x}

now solve this ,

161.6(19+x)=167*x+3038

3070.4+161.6*x=167*x+3038

3070.4-3038=167*x-161.6*x

32.4=5.4*x

x=32.4/5.4

<h2>x=6   Ans........</h2>

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3 years ago
The squre root of 290
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Answer: √290 ≈ 17.029386366.

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