Answer:
11
Step-by-step explanation:
1. <span>Suppose that a single card is selected from a standard 52-card deck. what is the probability that the card drawn is a club ?
From the total 52 card, there is 13 club card. There is no scenario that need to be considered in this problem. The probability to draw club would be:
the number of club cards/</span>total number of cards <span>= 13/52= 1/4= 25%
2. </span><span>suppose that a single card is drawn from a standard 52-card deck, but it is told that the card is black. what is the probability that the card drawn is a <span>club ?
</span></span>
In this scenario, the card is already known as black. Out of 52 cards, there is 26 black card. Out of 26 black cards, there are 13 clubs cards. The probability to draw club would be:
the number of club cards/total number of black cards= 13/26= 1/2= 50%
Hi!
To solve this, we need to know how much the earrings and necklace cost together, then we need to know if it's more or less than how much she has ($20)
So first, add the costs together.
7 . 5 8
+ 1 3 . 3 6
---------------
2 0 . 9 4
The necklace and earrings cost $20.94 which is more than $20.
The answer is no, Doreen does not have enough money.
Hope this helps! :)
-Peredhel
Answer:
m=6+2/3+3=8/6=4/3
y-y1=m(x-x1)
Y+2=4/3(x+3)
Y=4x/3 +4-2
y=4/3 x+2
Step-by-step explanation:
Answer:
(3x+2)(2x-5)(x³ -9)
Step-by-step explanation:
I like to use a graphing calculator to assist with factoring higher-degree polynomials. This polynomial has roots at -2/3, +5/2, and an irrational number near 2.08. The factors corresponding to the rational roots are (3x +2) and (2x -5).
Polynomial long division or synthetic division can be used to divide these out.
In each case, the divisor has a coefficient other than 1, so both dividend and divisor polynomials need to be divided by that coefficient before proceeding with synthetic division. (That is why there are fractions in the tableaux.)
The result is that the factorization in integers is ...

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The irrational roots are the three cube roots of 9, two of which are complex.
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Any of several different algorithms can tell you that the real roots will lie in the interval [-6, 6] or smaller. The rational roots will be of the form ...
±(divisor of 90)/(divisor of 6)