X - 5.7 = 6.4 what is x?

Mathematics

2 answers:

Evgen [1.6K]3 years ago

8 0

Answer:

The chosen topic is not meant for use with this type of problem. Try the examples below.

3x+3=243x+3=24

x2+9=73x2+9=73

x2−10x≤−9

Step-by-step explanation:

Hope this helps, If it did, then I would really appreciate it if you gave me Brainliest, I only need one more to rank up and it has taken forever to get to where I am currently. Thanks.

Sonbull [250]3 years ago

4 0

Answer: 12.1

Step-by-step explanation: 6.4+5.7=12.1 to see if your answer is correct all you have to do is 12.1-5.7=6.4

You might be interested in

2+2+2+2+2+2+2+10+10+2+2+2

DENIUS [597]

Answer:

40 lol

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Use the definition of continuity and the properties of limit to show that the function f(x)=x sqrtx/ (x-6)^2 is continuous at x=

jasenka [17]

Answer:

The function $\\ f(x) = \frac{x*\sqrt{x}}{(x-6)^{2}}$ is continuous at x = 36.

Step-by-step explanation:

We need to follow the following steps:

The function is:

$\\ f(x) = \frac{x*\sqrt{x}}{(x-6)^{2}}$

The function is continuous at point x=36 if:

The function $\\ f(x)$ exists at x=36.
The limit on both sides of 36 exists.
The value of the function at x=36 is the same as the value of the limit of the function at x = 36.

Therefore:

The value of the function at x = 36 is:

$\\ f(36) = \frac{36*\sqrt{36}}{(36-6)^{2}}$

$\\ f(36) = \frac{36*6}{900} = \frac{6}{25}$

The limit of the $\\ f(x)$ is the same at both sides of x=36, that is, the evaluation of the limit for values coming below x = 36, or 33, 34, 35.5, 35.9, 35.99999 is the same that the limit for values coming above x = 36, or 38, 37, 36.5, 36.1, 36.01, 36.001, 36.0001, etc.

For this case:

$\\ lim_{x \to 36} f(x) = \frac{x*\sqrt{x}}{(x-6)^{2}}$