Answer:
vfdsfdzdfgzdfgsadfga
Step-by-step explanation:
fcdsfhdsdfhzdbasaefga
Answer:
1.9 Seconds
Step-by-step explanation:
The equation that models the height of the object is given as:
![h=-16t^2+60](https://tex.z-dn.net/?f=h%3D-16t%5E2%2B60)
The object will land when its height, h(t)=0
![\text{When h(t)=0}\\-16t^2+60=0\\-16t^2=-60\\$Divide both sides by -16\\\dfrac{-16t^2}{-16} =\dfrac{-60}{-16}\\t^2=3.75\\t=\sqrt{3.75} \\t=1.94\:seconds\\\approx 1.9\:seconds $(to the nearest tenth)](https://tex.z-dn.net/?f=%5Ctext%7BWhen%20h%28t%29%3D0%7D%5C%5C-16t%5E2%2B60%3D0%5C%5C-16t%5E2%3D-60%5C%5C%24Divide%20both%20sides%20by%20-16%5C%5C%5Cdfrac%7B-16t%5E2%7D%7B-16%7D%20%3D%5Cdfrac%7B-60%7D%7B-16%7D%5C%5Ct%5E2%3D3.75%5C%5Ct%3D%5Csqrt%7B3.75%7D%20%5C%5Ct%3D1.94%5C%3Aseconds%5C%5C%5Capprox%201.9%5C%3Aseconds%20%24%28to%20the%20nearest%20tenth%29)
The object will land after 1.9 seconds.
Let's solve your system by substitution.
2
x
−
3
y
=
1
;
3
x
+
2
y
=
6
Step: Solve
2
x
−
3
y
=
1
for x:
2
x
−
3
y
=
1
2
x
−
3
y
+
3
y
=
1
+
3
y
(Add 3y to both sides)
2
x
=
3
y
+
1
2
x
2
=
3
y
+
1
2
(Divide both sides by 2)
x
=
3
2
y
+
1
2
Step: Substitute
3
2
y
+
1
2
for
x
in
3
x
+
2
y
=
6
:
3
x
+
2
y
=
6
3
(
3
2
y
+
1
2
)
+
2
y
=
6
13
2
y
+
3
2
=
6
(Simplify both sides of the equation)
13
2
y
+
3
2
+
−
3
2
=
6
+
−
3
2
(Add (-3)/2 to both sides)
13
2
y
=
9
2
13
2
y
13
2
=
9
2
13
2
(Divide both sides by 13/2)
y
=
9
13
Step: Substitute
9
13
for
y
in
x
=
3
2
y
+
1
2
:
x
=
3
2
y
+
1
2
x
=
3
2
(
9
13
)
+
1
2
x
=
20
13
(Simplify both sides of the equation)
Answer:
x
=
20
13
and
y
=
9
13
Answer:
21
Step-by-step explanation:
If y = 3 then multiply 5 x 3=15. Add 6 and you get 21. 21 is the correct answer.