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Alekssandra [29.7K]
3 years ago
5

If you apply the changes below to the absolute value parent function, F(x)=|x|, what is the equation of the new function? Shift

8 units left, shift 3 units down.
A. G(x)=|x-3|-8
B. G(x)=|x-3|+8
C. G(x)=|x-8|-3
G(x)=|x+8|-3
Mathematics
2 answers:
Nina [5.8K]3 years ago
7 0
The transformation that shifts a function along the x-axis is f(x+a), which shifts the function to the left, and f(x-a), which shifts the function to the right.

The transformation that shifts a function along the y-axis is f(x)+a, which shifts the function up, and f(x)-a, which shifts the function down

Hence, the correct answer is D: g(x)=f(x+8)-3
jeka57 [31]3 years ago
7 0

Answer:

d is the correct answer!

Step-by-step explanation:

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Which equation represents a line that passes through (4,1/3) and has a slope of 3/4?
scoray [572]

Step-by-step explanation:

With this kind of problem, we're looking at an equation in the form

y - y1 = m(x - x1)

(m = slope)

so we can substitute m, y1, and x1 with the values we're given.

y - y1 = m(x - x1)

y - 1/3 = 3/4(x - 4)

Answer:

y - 1/3 = 3/4(x - 4)

6 0
3 years ago
Draw two number lines that show 0.200 and 1/5 are equivalent
8090 [49]
<span>To draw two number lines showing that 0.200 and 1/5 are equivalent, we draw a number line divided into 5 equal segments with range from 0 to 1.0, the points on this line will be at 0.2,0.4,0.6,0.8 and 1.0. Next we draw second number line with range from 0 to 5/5 with 5 equal segments. The points on this line will be 1/5, 2/5,3/5,4/5 and 5/5. The equal segments will show that these values 0.200 and 1/5 are equivalent.</span>
4 0
3 years ago
Please please help me
Alex73 [517]

Answer:

x = 5.5

Step-by-step explanation:

Given 2 secants intersecting the circle from a point outside the circle then

The product of the external part and the entire part of one secant is equal to the product of the external part and the entire part of the other secant, that is

x(x + 14) = 6(6 + 12)

x² + 14x = 6 × 18 = 108 ( subtract 108 from both sides )

x² + 14x - 108 = 0 ← in standard form

with a = 1, b = 14 and c = - 108

Using the quadratic formula to solve for x

x = ( - b ± \sqrt{b^2-4ac} ) / 2a

  = ( - 14 ± \sqrt{14^2-(4(1)(-108)} ) / 2

  = ( - 14 ± \sqrt{196+432} ) / 2

  = ( - 14 ± \sqrt{628} ) / 2

  x = \frac{-14-\sqrt{628} }{2} or x = \frac{-14+\sqrt{628} }{2}

  x = - 19.5 or x = 5.5 ( to 1 dec. place )

However x > 0 ⇒ x = 5.5

6 0
3 years ago
Plz Help! I need this ASAP! I will give brainlest!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
viktelen [127]

7)  164.26

8)77.08

9)2405.364

steps for 7) attached

steps for 8)

7 0
3 years ago
If the equation below is solved by graphing, which statement is true?
adelina 88 [10]

Answer:

.46

Step-by-step explanation:

If you graph the function, you can see where the two logs intersects. View the image I have attached.

5 0
3 years ago
Read 2 more answers
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