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irina [24]
3 years ago
14

Expanded form of 5.921

Mathematics
1 answer:
myrzilka [38]3 years ago
3 0
5.000 + .900 + .020 + .001
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Set up and solve a system of equations to solve the problem.
Butoxors [25]

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The first Gym when he joins we will have to pay 60 dollars and in a 30 witch cost 90 dollers. but the second gym cost 50 $ per month so the first gym in a year he will pay 450$ and the second one 600 so the first one is cheeper.

Step-by-step explanation:

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Which number line shows the solutions to<br> 1/2x – 2 &gt; 0?
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This is the correct answer. x > 4

Step-by-step explanation:

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HELP!!! THIS IS DUE AT 11:59!
Misha Larkins [42]

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1. x = 22

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blagie [28]

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1850

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2 years ago
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John and Martha are contemplating having children, but John’s brother has galactosemia (an autosomal recessive disease) and Mart
Rina8888 [55]
<h2>Answer:</h2>

Probability=\frac{1}{24}

<h2>Step-by-step explanation:</h2>

As the question states,

John's brother has Galactosemia which states that his parents were both the carriers.

Therefore, the chances for the John to have the disease is = 2/3

Now,

Martha's great-grandmother also had the disease that means her children definitely carried the disease means probability of 1.

Now, one of those children married with a person.

So,

Probability for the child to have disease will be = 1/2

Now, again the child's child (Martha) probability for having the disease is = 1/2.

Therefore,

<u>The total probability for Martha's first child to be diagnosed with Galactosemia will be,</u>

Probability=\frac{2}{3}\times \frac{1}{2}\times \frac{1}{2}\times \frac{1}{4}\\Probability=\frac{1}{24}

(Here, we assumed that the child has the disease therefore, the probability was taken to be = 1/4.)

<em><u>Hence, the probability for the first child to have Galactosemia is \frac{1}{24}</u></em>

3 0
3 years ago
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