Answer:
Profit maximising price = 48
Explanation:
Total Cost : C (x) = 8x + 3
Demand Curve : p (x) = 88 − 2x
Total Revenue = p (x). x = x (88 - 2x) = 88x - 2x^2
Profit maximisation is where Marginal Cost (MC) = Marginal Revenue (MR)
MC = d TC / d Q = d (8x + 3) / d x = 8
MR = d TR / d Q = d (88x - 2x^2) / d x = 88 - 4x
Equating MR & MC ,
88 - 4x = 8 , 88 - 8 = 4x
x = 80 / 4 , x = 20
Putting value in demand curve,
p = 88 - 2x = 88 - 2 (20) = 88 - 40
p = 48
Answer:
Total number of equivalent units= 100,000
Explanation:
Giving the following information:
A total of 90,000 were finished during the period and 25,000 remaining in Work in Process inventory were 40% complete with respect to direct labor at the end of the period.
Weighted-average method:
Units completed= 90,000
Ending inventory= 25,000*0.4= 10,000
Total number of equivalent units= 100,000
This answer requires that we fill in the blanks
- The net present value (NPV) method estimates how much a potential project will contribute to shareholder wealth
- The larger the NPV, the more value the project adds; and added value means a higher stock price.
- The NPV calculation assumes that cash inflows can be reinvested at the project's risk-adjusted WACC
- When the firm is considering independent projects, if the project's NPV exceeds zero the firm should accept the project.
- When the firm is considering mutually exclusive projects, the firm should accept the project with the higher positive NPV.
What is the NPV?
In order to get the NPV we have to make the following calculations for the projects A and B.
This is calculated as
Project A
-900 + 620/1.08 + 395/1.08² + 200/1.08³ + 250/1.08⁴
= $355. 237
For the project B
We would have to perform similar calculation
Hence we would have
-900 + 620/1.08 + 395/1.08² + 200/1.08³ + 250/1.08⁴
= 378.98
From the calculations that we have done above, we can see that the value for project B is greater hence we have to choose project B.
Read more on NPV here:
brainly.com/question/17185385
#SPJ1
I believe the answer is by the portion.