Answer:
0
Step-by-step explanation:
Approximately 0.2% of the apples will be more than three standard deviations above the mean size. In a bin of 100 apples, 0.2% of 100=0.2% apples, this rounds down to zero apples that size or larger. (In a bin of 500 apples, there could be one apple of that size.)
Answer:
c. 6.2 ± 2.626(0.21)
Step-by-step explanation:
We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 101 - 1 = 100
99% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 100 degrees of freedom(y-axis) and a confidence level of
. So we have T = 2.626
The confidence interval is:

In which
is the sample mean while M is the margin of error.
The distribution of the number of puppies born per litter was skewed left with a mean of 6.2 puppies born per litter.
This means that 
The margin of error is:

In which s is the standard deviation of the sample and n is the size of the sample.
Thus, the confidence interval is:

And the correct answer is given by option c.
Answer:
Y = X - 2 would be the answer.
Answer:
8.1
Step-by-step explanation:
8.1 is the highest as you would look at the first number before the decimal and is the highest in this equation.