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mel-nik [20]
4 years ago
11

Please help with this!! i already did a bit idk if its right tho

Mathematics
1 answer:
Irina-Kira [14]4 years ago
6 0
What is it? You didn’t post anything?
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After running for 3 1/2 km, Sacha only completed half the total distance of a marathon . What is the complete distance of that m
Gre4nikov [31]

*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆**☆*――*☆*――*☆*――*☆

Answer: 7 km

Explanation:

3.5 x 2 = 7

I hope this helped!

<!> Brainliest is appreciated! <!>

- Zack Slocum

*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆**☆*――*☆*――*☆*――*☆

3 0
3 years ago
Read 2 more answers
The area of Ms. McCarthy’s garden measures 600 square feet. She plants vegetables in 75% of her garden and flowers in the remain
vlabodo [156]
75% is planted with vegetable
so (100-75)% = 25% is planted with flowers
so 25/100 * 600 = 150


Mark brainliest please
5 0
3 years ago
Answe 25 and 26 easy
Zina [86]

Answer:

25. rational

26. irrational

Step-by-step explanation:

A rational number is a number that can be written as a fraction. It may have decimals that end or repeating decimals.

An irrational number cannot be written as a fraction. It's decimals continue on and do not repeat.

25.

When you multiply two rational numbers, the product is rational. The square root of 16 is 4, which is rational because it is a whole number. 4/7 is written as a fraction so it is rational.

26.

The square root of 2 is an irrational number because its decimals go on and do not repeat. 7 is a whole number so it is rational. Subtracting a irrational number from a rational number gives an irrational number.

3 0
4 years ago
2. The metric system is based on units of<br> O A. 50.<br> O B. 10.<br> O C. 5.<br> OD. 20.
vaieri [72.5K]
The metric system units are based on the powers of 10.
6 0
2 years ago
What are the zeros of the quadratic function f(x) = 6x ^ 2 - 24x + 1 ?
ZanzabumX [31]

Answer:

x = \frac{12+\sqrt{138} }{6} and x = \frac{12-\sqrt{138} }{6}

Step-by-step explanation:

Let's use the quadratic formula, which states that for a quadratic of the form ax² + bc + c, the zeroes are: x=\frac{-b+\sqrt{b^2-4ac} }{2a} or x=\frac{-b-\sqrt{b^2-4ac} }{2a}.

Here, a = 6, b = -24, and c = 1. Plug these in:

x=\frac{-b+\sqrt{b^2-4ac} }{2a}

x=\frac{-(-24)+\sqrt{(-24)^2-4*6*1} }{2*6}=\frac{24+\sqrt{552} }{12}=\frac{24+2\sqrt{138} }{12} =\frac{12+\sqrt{138} }{6}

AND

x=\frac{-b-\sqrt{b^2-4ac} }{2a}

x=\frac{-(-24)-\sqrt{(-24)^2-4*6*1} }{2*6}=\frac{24-\sqrt{552} }{12}=\frac{24-2\sqrt{138} }{12} =\frac{12-\sqrt{138} }{6}

Thus, the zeroes are: x = \frac{12+\sqrt{138} }{6} and x = \frac{12-\sqrt{138} }{6}.

3 0
3 years ago
Read 2 more answers
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