Pls help me on this question !

Mathematics

1 answer:

bixtya [17]3 years ago

3 0

Kywettgffjfhdhdjddju

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Bryce has 220 feet of fencing that will enclosure a rectangular corral. One side of the corral will be 48 feet long. What will b

Gala2k [10]

Answer:

10560 square feet

Step-by-step explanation:

If 2 sides are 48 feet, then we are left with

$220-2*48=124$ feet for the remaining side pieces.

$\frac{124}{2} =62$ feet.

So our dimensions must be 48 x 62.

This gives us an area of

$220*48=10560ft^{2}$

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3 years ago

2sin 2x =1 ( 0 < x 2π )

yuradex [85]

Answer:

17pie/12

Step-by-step explanation:

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What is the result of substituting for y in the bottom equation y=x+3 y=x^2+2x-4

8_murik_8 [283]

The solutions are (2.1925, 5.1925) and (-3.1925, -0.1925)

Solution:

Given that,

$y = x + 3 ------- eqn 1\\\\y = x^2 + 2x - 4 ----- eqn 2$

We have to substitute eqn 1 in eqn 2

$x + 3 = x^2 + 2x - 4$

$\mathrm{Switch\:sides}\\\\x^2+2x-4=x+3\\\\\mathrm{Subtract\:}3\mathrm{\:from\:both\:sides}\\\\x^2+2x-4-3=x+3-3\\\\\mathrm{Simplify}\\\\x^2+2x-7=x\\\\\mathrm{Subtract\:}x\mathrm{\:from\:both\:sides}\\\\x^2+2x-7-x=x-x\\\\\mathrm{Simplify}\\\\x^2+x-7=0$

$\mathrm{Solve\:with\:the\:quadratic\:formula}\\\\\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\\mathrm{For\:}\quad a=1,\:b=1,\:c=-7\\\\x =\frac{-1\pm \sqrt{1^2-4\cdot \:1\left(-7\right)}}{2\cdot \:1}$