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natima [27]
3 years ago
9

Which graph shows the solutions to the inequality n<46

Mathematics
2 answers:
MaRussiya [10]3 years ago
7 0

Are there choices to the answer or must you draw the graph?

If you can please attach images so I can help :)

Pepsi [2]3 years ago
7 0

Can you please attach a image i really want to help

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Find x when y=5 if y varies inversely as x and x=6 when y =-18
Vera_Pavlovna [14]
It has been given that y varies inversely with x, therefore the equation for this relationship is as follows;
y =\frac{k}{x}\
when y = -18 and x = 6
-18 = k/ 6 ---1)
We need to find x when y = 5
 5 = k/x
when we divide 1)/2), k gets cancelled 

\frac{-18}{5}=  \frac{x}{6}
x = -18*6/5
x = -21.6
when y = 5, then x = -21.6
7 0
3 years ago
Elizabeth has 87.75 feet of banner paper how many banners can she make that are 11.25 feet long. explain
lana [24]
7.8 or if you are rounding it’s eight
6 0
3 years ago
W+1/8 =8 plzz help me i need it
Marina CMI [18]

Answer:

w = 7 7/8

Step-by-step explanation:

w + 1/8 = 8

First, subtract 1/8 from both sides of the equation

w + 1/8 = 8

   - 1/8    - 1/8

w = 7 7/8

8 0
3 years ago
Read 2 more answers
Find the square root of 64a^2/9b^2+4+32a/3b​
insens350 [35]

Answer:

the square root of 64a^2/9b^2+4+32a/3b is

  • ( 8a + 6b ) / 3b

or

  • 8a / 3b + 2

8 0
3 years ago
Draw at least six different sized rectangles that have an area of 64 square units
olga_2 [115]

Let

x------> the length of the rectangle

y------> the width of the rectangle

we know that

The area of a rectangle is equal to

A=x*y

A=64\ units^{2}

so

x*y=64 --------> equation 1

let's assume different values of x to get the different values of y

<u>case 1)</u> For x=64 units

substitute in the equation 1

x*y=64

y=64/x

y=64/64

y=1\ units      

the dimensions of the rectangle are 64 units x 1 unit

see the draw in the attached figure N 1

<u>case 2)</u> For x=32 units

substitute in the equation 1

x*y=64

y=64/x

y=64/32

y=2\ units

the dimensions of the rectangle are 32 units x 2 units

see the draw in the attached figure N 2

<u>case 3)</u> For x=16 units  

substitute in the equation 1

x*y=64

y=64/x

y=64/16

y=4\ units

the dimensions of the rectangle are 16 units x 4 units

see the draw in the attached figure N 3

<u>case 4)</u> For x=30 units

substitute in the equation 1

x*y=64      

y=64/x

y=64/30

y=\frac{32}{15} =2\frac{2}{15} \ units

the dimensions of the rectangle are 30 units x 2 (2/15) units

see the draw in the attached figure N 4

<u>case 5)</u> For x=40 units

substitute in the equation 1

x*y=64    

y=64/x

y=64/40

y=1.60\ units

the dimensions of the rectangle are 40 units x 1.60 units

see the draw in the attached figure N 5

<u>case 6)</u> For x=60 units

substitute in the equation 1

x*y=64    

y=64/x

y=64/60

y=\frac{16}{15} =1\frac{1}{15} \ units

the dimensions of the rectangle are 60 units x 1 (1/15) units

see the draw in the attached figure N 6

3 0
3 years ago
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