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soldier1979 [14.2K]
4 years ago
11

Four consecutive positive prime numbers have a sum that is divisible by three. What is the smallest possible value of this sum?

Mathematics
1 answer:
LuckyWell [14K]4 years ago
4 0

Answer:

36

Step-by-step explanation:

1 + 3 + 5 + 7 = 16

3 + 5 + 7 + 11= 26

These consecutive positive prime numbers above have sums that are not divisible by three.

5 + 7 + 11 + 13 = 36

This consecutive positive prime numbers above has a sum that is divisible by three: 36.

36 : 3 = 12

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