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Thepotemich [5.8K]
3 years ago
13

The following data represent the muzzle velocity​ (in feet per​second) of rounds fired from a​ 155-mm gun. For each​ round, two

measurements of the velocity were recorded using two different measuring​ devices, resulting in the following data. Complete parts​ (a) through​ (d) below.
Observation

1

2

3

4

5

6

A

790.2790.2

791.3791.3

791.4791.4

793.7793.7

793.4793.4

793.3793.3

B

800.1800.1

789.7789.7

799.8799.8

792.6792.6

802.1802.1

788.5788.5

​(a) Why are these​ matched-pairs data?

A.Two measurements​ (A and​ B) are taken on the same round.

B.All the measurements came from rounds fired from the same gun.

C.The same round was fired in every trial.

D.The measurements​ (A and​ B) are taken by the same instrument.

​(b) Is there a difference in the measurement of the muzzle velocity between device A and device B at the

alpha equals 0.01α=0.01

level of​ significance? ​Note: A normal probability plot and boxplot of the data indicate that the differences are approximately normally distributed with no outliers.Let

di=Ai−Bi.

Identify the null and alternative hypotheses.

Upper H 0H0​:

Upper H 1H1​:

Determine the test statistic for this hypothesis test.

t0=

​(Round to two decimal places as​ needed.)

Find the​ P-value.

​P-valuee=

​(Round to three decimal places as​ needed.)What is your conclusion regarding

Upper H 0=

α=0.01

level of significance to conclude that there is a difference in the measurements of velocity between device A and device B.

​(c) Construct a​ 99% confidence interval about the population mean difference. Compute the difference as device A minus device B. Interpret your results.

The confidence interval is left parenthesis nothing comma nothing right parenthesis .,.

​(Round to two decimal places as​ needed.)

Interpret the confidence interval. Choose the correct answer below.

A.One can be​ 1% confident that the mean difference in measurement lies in the interval found above.

B.One can be​ 99% confident that the mean difference in measurement is 0.01

C.One can be​ 99% confident that the mean difference in measurement lies in the interval found above.

D.One can be​ 99% confident that the mean difference in measurement is 0.

​

Does this visual evidence support the results obtained in part​(b)?

A.​Yes, because 0 is contained in the boxplot.

B.No, because the boxplot is too large.

C.No, because 0 is not containednot containedin the boxplot.

D.Yes, because the boxplot shows no outliers.
Mathematics
2 answers:
blondinia [14]3 years ago
6 0

Answer:

what are you suppose to be figuring out?

Step-by-step explanation:

Alla [95]3 years ago
5 0
I believe the first one is answer B I do not know the rest
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Step-by-step explanation:

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MrRa [10]

Answer:

MN = 160

Step-by-step explanation:

We know that arc MN = arc NO

17g - 10 = 14g+ 20

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Answer:

\theta=\frac{2A}{r^2}

Step-by-step explanation:

Given : The formula A=\frac{\theta r^2}{2}

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Gcf of 20 time 76 is 4
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Answer:

28.

a. false

b. true

c. false

d. false

2. 8.4 X 2.3 X 2.09 = 40.3788

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