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DanielleElmas [232]
3 years ago
7

I need help answering this question.

Mathematics
2 answers:
Darina [25.2K]3 years ago
7 0
Her credits need to be AT LEAST EQUAL TO OR GREATER THAN 144 (credit hours) so we can eliminate choices B and D.

She already completed 4 semesters in which she receives 15 credit per semester.

This expression can be written as 4(15).

She needs to do a certain remaining hours of credit which can be represented by c and only c without any other coefficient.

So, the most reasonable choice here is A.
shtirl [24]3 years ago
4 0
The answer is D 4(15)+c < 144
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The vertices of triangle JKL, shown below, are J(2, 1), K(4, 4), and L(6, 2). If triangle JKL is translated 2 units to the left
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Step-by-step explanation:Left = -2 units and down = -4 units, left is x direction and down is y direction. (x,y).

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Ms. Joseph wants to take her mother to see the Color Purple. Tickets in the mezzanine cost $140
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The ans is simple

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Step-by-step explanation:

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3 years ago
Find the distance and midpoint of a segment with the following endpoints: (5,-1) and (-9,-1)
Likurg_2 [28]

Answer:

d = 14

(-2,-1)

General Formulas and Concepts:

  • Order of Operations: BPEMDAS
  • Distance Formula: d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}
  • Midpoint Formula: (\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})

Step-by-step explanation:

<u>Step 1: Define</u>

(5, -1)

(-9, -1)

<u>Step 2: Find distance </u><em><u>d</u></em>

  1. Substitute:                    d = \sqrt{(-9-5)^2+(-1-(-1))^2}
  2. Simplify:                        d = \sqrt{(-9-5)^2+(-1+1)^2}
  3. Subtract/Add:               d = \sqrt{(-14)^2+(0)^2}
  4. Evaluate:                       d = \sqrt{196}
  5. Evaluate:                       d = \14

<u>Step 3: Find Midpoint</u>

  1. Substitute:                    (\frac{5-9}{2},\frac{-1-1}{2})
  2. Subtract:                       (\frac{-4}{2},\frac{-2}{2})
  3. Divide:                          (-2,-1)
7 0
3 years ago
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