Convert 1254 kilocakories to calories

Where does carriage comes in Financial statements?

ratelena [41]

Answer:

Carriage outwards is also referred to as freight-out, transportation-out, or delivery expense. The cost of carriage outwards should be reported on the income statement as an operating expense in the same period as the revenue from the sale of the goods.

8 0

2 years ago

The legs of a right triangle are 10 cm and 24 cm. What is the length of the hypotenuse?

n200080 [17]

To determine the length of the hypotenuse, apply Pythagorean theorem.

A^2 + B^2 = C^2
(10)^2 + (24)^2 = C^2
100 + 576 = C^2
676 = C^2
C = 26 cm.

The hypotenuse is 26 cm.

6 0

3 years ago

Read 2 more answers

Simplify the expression. What classification describes the resulting polynomial? (3x^2-11x-4)-(2x^2-x-6)

Gnoma [55]

The expression can be simplified to a polynomial of degree 2.

$x^2 - 10x + 2$

<h3>How to simplify the expression?</h3>

Here we have the expression:

$(3x^2 -11x - 4) - (2x^2 - x - 6)$

We can directly simplify this by taking the variable as common factor:

$(3 - 2)*x^2 + (-11 + 1)*x + (-4 + 6)\\\\x^2 - 10x + 2$

This is a polynomial, as you can see, the maximum exponent is 2, so the degree of the polynomial is 2.

If you want to learn more about polynomials:

brainly.com/question/4142886

#SPJ1

8 0

1 year ago

The Oregon Department of Health web site provides information on the cost-to-charge ratio (the percentage of billed charges that

Alekssandra [29.7K]

Answer:

We conclude that the mean cost-to-charge ratio for Oregon hospitals is lower for outpatient care than for inpatient care.

Step-by-step explanation:W

We are given with the cost-to-charge ratios for both inpatient and outpatient care in 2002 for a sample of six hospitals in Oregon below;

Hospital 2002 Inpatient Ratio 2002 Outpatient Ratio

1 68 54

2 100 75

3 71 53

4 74 56

5 100 74

6 83 71

Let $\mu_1$ = mean cost-to-charge ratio for outpatient care

$\mu_2$ = mean cost-to-charge ratio for impatient care.

SO, Null Hypothesis, $H_0$ : $\mu_1 \geq \mu_2$ {means that the mean cost-to-charge ratio for Oregon hospitals is higher or equal for outpatient care than for inpatient care}

Alternate Hypothesis, $H_A$ : $\mu_1 < \mu_2$ {means that the mean cost-to-charge ratio for Oregon hospitals is lower for outpatient care than for inpatient care}

The test statistics that would be used here is Two-sample t-test statistics because we don't know about population standard deviations;

T.S. = $\frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }$ ~ $t__n__1_+_n_2_-_2$

where, $\bar X_1$ = sample mean cost-to-charge Outpatient Ratio = $\frac{\sum X_1}{n_1}$ = 63.83

$\bar X_2$ = sample mean cost-to-charge Impatient Ratio = $\frac{\sum X_2}{n_2}$ = 82.67

$s_1$ = sample standard deviation for Outpatient Ratio = $\sqrt{\frac{\sum (X_1-\bar X_1 )^{2} }{n_1-1} }$ = 10.53

$s_2$ = sample standard deviation for Impatient Ratio = $\sqrt{\frac{\sum (X_2-\bar X_2 )^{2} }{n_2-1} }$ = 14.33

$n_1$ = sample of hospital for outpatient care = 6

$n_2$ = sample of hospital for outpatient care = 6

Also, $s_p=\sqrt{\frac{(n_1-1)s_1^{2}+(n_2-1)s_2^{2} }{n_1+n_2-2} }$ = $\sqrt{\frac{(6-1)\times 10.53^{2}+(6-1)\times 14.33^{2} }{6+6-2} }$ = 12.574

So, the test statistics = $\frac{(63.83-82.67)-(0)}{12.574 \times \sqrt{\frac{1}{6}+\frac{1}{6} } }$ ~ $t_1_0$

= -2.595

The value of t test statistics is -2.595.

Now, at 5% significance level, the t table gives critical value of -1.812 at 10 degree of freedom for left-tailed test.

Since, our test statistics is less than the critical value of t as -2.595 < -1.812, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that the mean cost-to-charge ratio for Oregon hospitals is lower for outpatient care than for inpatient care.

8 0

3 years ago

Val rented a bicycle while she was on vacation. She paid a flat rental fee of $55.00, plus $8.50

Oksana_A [137]

55 + 8.50d = 123

55 for rental
8.50d for each day she pays 8.50 so add the d and then equal sign and 123.

3 0

2 years ago

Read 2 more answers