Answer:
D..........
Step-by-step explanation:
rgW
Hey there! :)
Answer:
Third option. x = 2, and x = 4.
Step-by-step explanation:
Find the zeros of this quadratic equation by factoring:
f(x) = x² - 6x + 8
Becomes:
f(x) = (x - 4)(x - 2)
Set each factor equal to 0 to solve for the roots;
x - 4 = 0
x = 4
x - 2 = 0
x = 2
Therefore, the zeros of this equation are at x = 2, and x = 4.
I cant see all of 11 and 14
12:
13:
15:
16:
Answer:
1
Step-by-step explanation:
Example: 2×1/2=1
.....
X = 4 ; x = 3 + i ; x = 3 - i
(If you get a zero that is adding or subtracting, you always need to write it twice but change the sign do they cancel out)
f(x) = (x-4)(x-3-i)(x-3+i)
Distributing the last two parenthesis first is always the best way to start off
(x-3-i)(x-3+i) has (x-3) in common so it can be separated to
(x-3)^2 + (-i)(+i)
(x^2 - 6x + 9) ; (-i)(+i) is always +1
(x^2 - 6x + 9) + 1
(x^2 - 6x + 10)
Now multiply this with (x-4)
x^3 - 6x^2 + 10x
- 4x^2 + 24x - 40
x^3 - 10x^2 + 34x - 40 = f(x)
