Ask question

Ask question

All categories

2 years ago

7

Que dimensiones de superficie mínimas tendría que tener la platea donde se armara el tanque australiano que tiene un diámetro de

3,80 metros y una altura de 47 centímetros

1 answer:

shusha [124]2 years ago

8 0

Answer:

LET GOOOOO

Step-by-step explanation:

You might be interested in

Vertex A in quadrilateral ABCD lies at (-3, 2). If you rotate ABCD 180° clockwise about the origin, what will be the coordinates

natali 33 [55]

The rule for a rotation by 180° about the origin is (x,y) -->(−x,−y)

So A(-3, 2) to A'(3, -2)

Answer:

A'(3, -2)

4 0

2 years ago

Rose’s Ringlets, a national hair salon, pays the following in employee benefits each pay period: $700 for health care, 10% of gr

Deffense [45]

Answer:

D $1298

Step-by-step explanation:

10% of 5200 is 520

1% is 52

0.5% is 26

700+520+52+26 = 1298

3 0

2 years ago

George had 50.00 he bought a pair of pants for 39.59 and a tire for 8.75 what is the total amount of money that he has left

noname [10]

$1.66 because 50-39.59=10.40 so it would also add $8.75 so that = $1.66

3 0

2 years ago

The work of a student trying to solve the equation 3(4x − 2) = 9 + 2x + 5 is shown below:

galina1969 [7]

Step 1 gives you
3*(4x - 2) on the left hand side.

When you remove the brackets what you get is
3*4x - 3*2
12 x - 6 You have to distribute on both sides of the plus sign. The answer is the second one down.

So the answer is 2) <<<< answer.

8 0

2 years ago

Read 2 more answers

g A manufacturer is making cylindrical cans that hold 300 cm3. The dimensions of the can are not mandated, so to save manufactur

sdas [7]

Answer:

The dimensions that minimize the cost of materials for the cylinders have radii of about 3.628 cm and heights of about 7.256 cm.

Step-by-step explanation:

A cylindrical can holds 300 cubic centimeters, and we want to find the dimensions that minimize the cost for materials: that is, the dimensions that minimize the surface area.

Recall that the volume for a cylinder is given by:

$\displaystyle V = \pi r^2h$

Substitute:

$\displaystyle (300) = \pi r^2 h$

Solve for <em>h: </em>

$\displaystyle \frac{300}{\pi r^2} = h$

Recall that the surface area of a cylinder is given by:

$\displaystyle A = 2\pi r^2 + 2\pi rh$

We want to minimize this equation. To do so, we can find its critical points, since extrema (minima and maxima) occur at critical points.

First, substitute for <em>h</em>.

$\displaystyle \begin{aligned} A &= 2\pi r^2 + 2\pi r\left(\frac{300}{\pi r^2}\right) \\ \\ &=2\pi r^2 + \frac{600}{ r} \end{aligned}$

Find its derivative:

$\displaystyle A' = 4\pi r - \frac{600}{r^2}$

Solve for its zero(s):

$\displaystyle \begin{aligned} (0) &= 4\pi r - \frac{600}{r^2} \\ \\ 4\pi r - \frac{600}{r^2} &= 0 \\ \\ 4\pi r^3 - 600 &= 0 \\ \\ \pi r^3 &= 150 \\ \\ r &= \sqrt[3]{\frac{150}{\pi}} \approx 3.628\text{ cm}\end{aligned}$

Hence, the radius that minimizes the surface area will be about 3.628 centimeters.

Then the height will be:

$\displaystyle \begin{aligned} h&= \frac{300}{\pi\left( \sqrt[3]{\dfrac{150}{\pi}}\right)^2} \\ \\ &= \frac{60}{\pi \sqrt[3]{\dfrac{180}{\pi^2}}}\approx 7.25 6\text{ cm} \end{aligned}$

In conclusion, the dimensions that minimize the cost of materials for the cylinders have radii of about 3.628 cm and heights of about 7.256 cm.

7 0

2 years ago