Answer:
7
r
Step-by-step explanation:
-1.32.9-0.6r
-2.9 -2.9
-4.2 ≥ -0.6r
/-0.6 /-0.6
7 ≥ r
Answer: ( -0.731, 0.682)
Step-by-step explanation:
The unit vector is defined as a vector that points in the same direction as our vector (137 degrees from the x-axis) and has a magnitude of 1.
Knowing the angle, is really simple to do it.
First, we know that for a radius R and an angle A, the rectangular coordinates can be written as:
x = R*cos(A)
y = R*sin(A)
And if we want that the magnitude/modulus of our vector to be 1, then R = 1, and we know that A = 137°
x = 1*cos(137°) = -0.731
y = 1*sin(137°) = 0.682
Then the unit vector is: ( -0.731, 0.682)
Answer:
60
Step-by-step explanation:
5 times 12
1.) f(x)=7(b)^x-2
x=0→f(0)=7(b)^0-2=7(1)-2=7-2→f(0)=5→(x,f(x))=(0,5) Ok
2.) f(x)=-3(b)^x-5
x=0→f(0)=-3(b)^0-5=-3(1)-5=-3-5→f(0)=-8→(x,f(x))=(0,-8) No
3.) f(x)=5(b)^x-1
x=0→f(0)=5(b)^0-1=5(1)-1=5-1→f(0)=4→(x,f(x))=(0,4) No
4.) f(x)=-5(b)^x+10
x=0→f(0)=-5(b)^0+10=-5(1)+10=-5+10→f(0)=5→(x,f(x))=(0,5) Ok
5.) f(x)=2(b)^x+5
x=0→f(0)=2(b)^0+5=2(1)+5=2+5→f(0)=7→(x,f(x))=(0,7) No
Answers:
First option: f(x)=7(b)^x-2
Fourth option: f(x)=-5(b)^x+10
As far as the old dimensions of the photo are concerned,
Width of the photo = 3"
Length of the photo = 5"
New length of the photo = 7 inches
Let us assume the new width of the photo = x inches
Then
3/5 = x/7
5x = 7 * 3
5x = 21
x = 21/5
= 4.20 inches
So the correct option among all the options that are given in the question is the first option. I hope that the answer has come to your help.
