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damaskus [11]
3 years ago
11

Bill wants to rent a car. Rental Company A charges $35 per day plus $0.10 per mile driven. Rental Company B charges $25 per day

plus $0.15 per mile driven. After how many miles driven will the price charged by each company be the same? Write and Solve the equation
Mathematics
1 answer:
svetoff [14.1K]3 years ago
7 0
200 miles write the equation as 35+0.10x=25+0.15x 
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Hitman42 [59]

{ \red{ \bold{option \: (c)}}}

Step-by-step explanation:

{ \purple{ \tt{ { - 5x}^{2}  + 10x}}}

Take { \purple{ \tt{5x}}}as common. Then,

{ \purple{ \tt{5x( - x + 2)}}}

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1 year ago
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masha68 [24]

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Hey Bestie! 50 pts Pls help! Real answers only pls &lt;3
frosja888 [35]

Answer:

1. \: 3i

2. option D

3. option C

4. option D

5. option C

6. option B

7. option C

8. option D

9. option C

10. option C

Step-by-step explanation:

<h2>1. \:  \sqrt{ - 9}</h2>

\sqrt{ - 1(9)}

\sqrt{ - 1}  \times  \sqrt{  9}

i \times  \sqrt{9}

i \times  \sqrt{ {3}^{2} }

i \times 3

3i

<h2>2. \:  \sqrt{ - 8}</h2>

\sqrt{ - 1(8)}

\sqrt{ - 1}  \times  \sqrt{8}

i \times  \sqrt{8}

i \times  \sqrt{ {2}^{2} \times 2 }

2i \sqrt{2}

<h2>3. \:  \sqrt{ - 80}</h2>

\sqrt{ - 1}  \times  \sqrt{80}

i \times  \sqrt{80}

4i \:  \sqrt{5}

<h2>4. \:  \sqrt{ - 75}</h2>

\sqrt{ - 1}  \times   \sqrt{75}

i \times  \sqrt{75}

i \times  \sqrt{ {5}^{2} \times 3 }

5i \sqrt{3}

<h2>5. \:  \sqrt{ - 72}</h2>

\sqrt{ - 1}  \times  \sqrt{72}

i \times  \sqrt{72}

i \times ( {6}^{2}  \times 2)

6i \sqrt{2}

<h2>6.  \sqrt{ - 20}</h2>

\sqrt{ - 1}  \times  \sqrt{20}

i \times  \sqrt{20}

i \times  \sqrt{ {2}^{2}  \times 5}

2i \sqrt{5}

<h2>7. \:  \sqrt{ - 27}</h2>

\sqrt{ - 1}  \times  \sqrt{27}

i \times  \sqrt{27}

i \times  \sqrt{ {3}^{2}  \times 3}

3i \sqrt{3}

<h2>8. \:  \sqrt{ - 12}</h2>

\sqrt{ - 1 \times 12}

i \times  \sqrt{12}

i \times  \sqrt{4(3)}

2i \sqrt{3}

<h2>9. \:  \sqrt{ - 125}</h2>

\sqrt{ - 1}  \times  \sqrt{125}

i \times  \sqrt{ {5}^{2} \times 5 }

5i \sqrt{5}

<h2>10. \:  \sqrt{ - 180}</h2>

\sqrt{ - 1}  \times  \sqrt{180}

i \times  \sqrt{ {6}^{2} \times 5 }

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<h3>Hope it is helpful...</h3>
5 0
3 years ago
Ma=np,for a is what<br>​
Julli [10]

Answer:

\displaystyle \frac{np}{m} = a

Step-by-step explanation:

You divide both sides by <em>m</em><em> </em>to get the above answer:

\displaystyle \frac{ma}{m} = \frac{np}{m} \\ \\ a = \frac{np}{m}

I am joyous to assist you anytime.

8 0
3 years ago
two ships leave a port at the same time. the first ship sails on a bearing of 55° at 12 knots (natural miles per hour) and the s
Korvikt [17]

Answer:

37.59 nautical miles

Explanation:

Distance = Speed x Time

The speed of the first ship = 12 knots

Thus, the distance covered after 1.5 hours

\begin{gathered} =12\times1.5 \\ =18\text{ miles} \end{gathered}

The speed of the second ship = 22 knots

Thus, the distance covered after 1.5 hours

\begin{gathered} =22\times1.5 \\ =33\text{ miles} \end{gathered}

The diagram representing the ship's path is drawn and attached below:

The angle at port = 90 degrees.

The triangle is a right triangle.

Using Pythagorean Theorem:

\begin{gathered} c^2=a^2+b^2 \\ c^2=18^2+33^2 \\ c^2=324+1089 \\ c^2=1413 \\ c=\sqrt[]{1413} \\ c=37.59\text{ miles} \end{gathered}

The two ships are 37.59 nautical miles apart after 1.5 hours.

8 0
1 year ago
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