All categories

3 years ago

Please help i'm struggling with this!It's urgent!

Mathematics

2 answers:

adell [148]3 years ago

6 0

Answer:

Well let me help you with 12! :)

Step-by-step explanation:

Wellit really isn't adding it is a pattern. So you see 1, 6, 11, 16? See the pattern of how it is only with the numbers 1 and 6 and and it goes like 1, 6, 11, 16, then you keep going.

Your Welcome! :)

tia_tia [17]3 years ago

3 0

Answer:

12 should be 41

Step-by-step explanation:

12) the pattern is an increase by 5 each time. This would mean the 8th term is 40. However, it starts at 1, so you should add 1 to this answer, making it 41. This pattern is y=5x+1 if x is that number in the pattern and y is the answer.

You might be interested in

Help me thankyouuuuuuu

erica [24]

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⢀⣀⣀⣀⣀⣀⣀⣀⣀⠀⠀⠀⠀⠀⠀⠀

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠻⡿⠛⠛⠛⠛⠻⢿⡿⠃⠀⠀⠀⠀⠀⠀

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⡄⡇⠀⠀ ⠀⠈⡇⠀⠀⠀⠀⠀⠀⠀

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠠⣧⣇⠀⠀⠀⣀⣤⣶⣷⠀⠠⠀⠀⠀⠀⠀

⠀⣀⠀⣠⣤⢀⣀⣠⣤⣤⣤⣤⣤⣿⣿⣿⣄⣼⣿⣿⣿⣿⣿⣿⣿⣦⣀⠀⠀⠀

⢰⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⡿⠛⠛⠛⠛⠻⣿⣷⠀⠀

⣸⣿⣿⣿⡿⠛⠛⠛⠻⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⡏⠀⠀⠀⠀⠀⠀⠘⣿⡷⠀

⠻⢿⣿⡏⠀⠀⣶⠀⠀⢻⣿⣿⣿⣿⣿⣿⣿⣿⣿⡄⠀⠀⠀⠀⠀⠀⠀⣿⣧⣀

⠀⠀⢹⣷⡀⠀⠀⠀⢀⣿⣿⣉⡉⠉⠉⠉⠉⢙⣿⣷⣄⠀⠀⠀⠀⢀⣼⣿⠛⠓

⠀⠈⠛⠛⠛⠓⠒⠚⠛⠛⠛⠛⠛⠋⠙⠛⠛⠛⠛⠟⠿⠷⠶⠶⠾⠿⢿⠿⠿⠿ Don't mind me, just a feller out on the farm.

4 0

2 years ago

Read 2 more answers

Divide the equation.

Aleksandr-060686 [28]

Answer:

3y+3

Step-by-step explanation:

I hope this works

7 0

2 years ago

In how many ways can 3person study groups beselected from a class of 25students?Note: nrn!r!(n-r)!nEnter

nlexa [21]

Answer:

2,300

Explanation:

This is given as:

$\begin{gathered} 25\text{ combination 3 represented as:} \\ ^nC_r=\frac{n!}{r!(n-r)!} \\ n=25 \\ r=3 \\ ^{25}C_3=\frac{25!}{3!(25-3)!} \\ ^{25}C_3=\frac{25\times24\times23\times22!}{3!\times22!} \\ ^{25}C_3=\frac{25\times24\times23}{3\times2\times1} \\ ^{25}C_3=2300 \end{gathered}$

Therefore, there are 2,300 ways that 3 persons can be selected from 25 people

8 0

1 year ago

The walls and ceiling of a storage shed are made of aluminum.

Dmitriy789 [7]

I believe the answer is B.

3 0

3 years ago

Read 2 more answers

A class consists of 55% boys and 45% girls. It is observed that 25% of the class are boys and scored an A on the test, and 35% o

Julli [10]

Step-by-step explanation:

Probability of event A on the condition of event B is:

P(A|B) = P(A and B) / P(B)

P(scored an A | girl) = P(scored an A and girl) / P(girl)

P(scored an A | girl) = 0.35 / 0.45

P(scored an A | girl) = 0.778

The probability that a randomly selected girl also scored an A is 77.8%.

7 0

3 years ago