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Gwar [14]
4 years ago
10

$64 jacket 20% discount

Mathematics
1 answer:
tatiyna4 years ago
3 0
$64 jacket with a 20% discount:

First, we need to change the percentage into a number that we can calculate with. Take the percentage (20%) and divide it by 100(%), since the denominator should always be 100 when changing a percentage into a decimal. 
\frac{20}{100} = 0.20

Now that we have a number we can calculate with, we need to know how much money we are going to save from the discount. Take the new decimal we just got, and multiply it by the cost of the jacket, which is $64. 
0.20 × 64 = 12.80

Knowing that we can save $12.40 on the jacket, we can now subtract the price of the jacket from the discount we get on it. 
64 - 12.80 = 51.20

You will pay a total of $51.20 on the jacket with the discount added.

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Please show me how to solve for z<br> 8-12z=92
NeTakaya

Answer: z = -7

Step-by-step explanation:

Simplify the equation so the Integer is on the right:

8 - 12z = 92

-12z + 8 = 92

Now subtract 8 from both sides:

-12z + 8 - 8 = 92 - 8

-12z = 84

Now divide both sides by 12 to get z by itself:

-12z/-12 = 84/-12

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7 0
3 years ago
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Im giving 100 Points to anyone who could solve this for me please.
myrzilka [38]

Answer:

AB = 27.2

BC = 33.5

AC = 50.4

∠A = 38°

∠ABC = 112°

Step-by-step explanation:

<u>Trigonometric ratios</u>

\sf \sin(\theta)=\dfrac{O}{H}\quad\cos(\theta)=\dfrac{A}{H}\quad\tan(\theta)=\dfrac{O}{A}

where:

  • \theta is the angle
  • O is the side opposite the angle
  • A is the side adjacent the angle
  • H is the hypotenuse (the side opposite the right angle)

\implies \sf \cos(30^{\circ})=\dfrac{29}{BC}

\implies \sf BC=\dfrac{29}{\cos(30^{\circ})}

\implies \sf BC=\dfrac{58\sqrt{3}}{3}=33.5\:(nearest\:tenth)

\implies \sf \tan(30^{\circ})=\dfrac{BD}{29}

\implies \sf BD=29\tan(30^{\circ})

\implies \sf BD=\dfrac{29\sqrt{3}}{3}

\implies \sf \sin(38^{\circ})=\dfrac{BD}{AB}

\implies \sf AB=\dfrac{\dfrac{29\sqrt{3}}{3}}{\sin(38^{\circ})}

\implies \sf AB=27.2\:(nearest\:tenth)

\implies \sf \tan(38^{\circ})=\dfrac{BD}{AD}

\implies \sf AD=\dfrac{\dfrac{29\sqrt{3}}{3}}{\tan(38^{\circ})}

\implies \sf AD=21.4\:(nearest\:tenth)

\implies \sf AC=AD+DC=21.4+29=50.4

The interior angles of a triangle sum to 180°

⇒ ∠A + 52° + 90° = 180°

⇒ ∠A = 180° - 90° - 52°

⇒ ∠A = 38°

⇒ ∠ABC + 38° + 30° = 180°

⇒ ∠ABC = 180° - 38° - 30°

⇒ ∠ABC = 112°

**I have checked the measures using a graphing programme - see attached**

8 0
2 years ago
Need help asap! Thanksss
Orlov [11]
The correct answer is 558
3 0
3 years ago
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If m DBC = 25x+ 7 and m TBC = 12x+ 5 =, find the degree measures of TBC, DBT, and DBC.
AlladinOne [14]
I honestly don't know any of this so
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Central Park in New York City is shaped like a rectangle. On a map of the park
mariarad [96]

Answer:

6

Step-by-step explanation:

Given that the coordinate plane, three of the vertices of the rectangle are located at (-1.25, -0.25),

(-1.25, 0.25), and (1.25, 0.25)

The length L of the shape will be:

L = 0.25 - ( - 0.25 )

L = 0.25 + 0.25

L = 0.5

The width of the shape will be:

W = 1.25 - ( - 1.25)

W = 1.25 + 1.25

W = 2.5

Perimeter P = 2L + 2W

Substitute the Length and the width into the formula

P = 2(0.5) + 2(2.5)

P = 1 + 5

P = 6 metres

Therefore, the perimeter of the shape is 6 metres

7 0
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