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aliya0001 [1]
4 years ago
8

Why do we use letters in mathematics?

Mathematics
2 answers:
Korolek [52]4 years ago
6 0
I would say we use letters in mathematics so you can understand the problem more or whats really happening for example if they ask you question about how many people went to the party and bought stuff without the letters and only numbers you'll be confused...like umm...how many people went what are the stuff they bought.Or another example is if the question only had an empty graph.People would be like what do I have to do with the empty graph.What's the problem etc.So math problems without letters would be confusing.
icang [17]4 years ago
3 0
We use letters to substitute for unknown numbers. I hope this helps. :)
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4. The population of Bay Village is 35,000 today. Every year the
frosja888 [35]

Answer:

Linear Model:   y(x)=35,000+750x

Step-by-step explanation:

In principle <em>Linear Models </em>are employed when we want to define a relationship between an independent and a dependent variable. <em>Linear Models</em> are also known as<em> Functions </em>, where one variable is expressed as a function of <em>at least one</em> other variable. The most common example would be a dependent variable y that is directly linked as a response to any changes of an independent variable x. The most common expression of such relationship would be y=ax where a is the relationship factor between y and x and is also known as the <em>slope </em>of the function (representing a rate of change of that function).

In this question we are told that the population of Bay Village today is 35,000. So we know this is our constant variable, lets call it  b.

Next we know that every year the population is increased by 750 people. So we know that our variable and thus our independent variable is every year which we shall call x and our fixed factor is the 750 increment which we will call a.  

From that we can conclude that:

<em>Year 1 Population: 35,000</em>

<em>Year 2 Population: 35,000 + 750 = 35,750</em>

<em>Year 3 Population: 35,750 + 750 = 36,500 </em>

And so on and so forth.<em> </em>

So we want to express the above as a Linear Model of the form:

<em> y = ax + b   </em>Eqn(1).

Thus from Eqn (1) and all information given (i.e. pluging in values) we finally obtain:

y(x)=35,000+750x

Which for every different value of  x (i.e. every year) we can obtain the new and increased population  y(x).

7 0
3 years ago
The minute hand on a clock made a 1-4 turn. How many degrees did the minute hand turn?
masha68 [24]
Your answer is 45 degrees
4 0
3 years ago
Read 2 more answers
Please help very confused! How do you graph the solution set to a system of linear inequalities in two variables?
BlackZzzverrR [31]
<h3>Step-by-step explanation:</h3>

We will use as an example the following system of inequalities:

  • 3x +2y ≥ 5x -4
  • y < (1/2)x +3

For each inequality, do the following:

1. If it is not this way already, arrange the inequality so that each variable appears on only one side of the inequality. Putting the inequality into any of the standard forms will do this. It will be helpful later if you arrange the inequality so that at least one variable has a positive coefficient. (You may have to multiply by -1 (and change the sense of the inequality) to do this.)

Our example inequalities are now ...

  • -2x +2y ≥ -4 . . . . . or divide by 2 to get . . . . -x +y ≥ -2
  • y < (1/2)x +3

2. Notice the inequality symbol, and whether it includes the "or equal to" case.

  • the first inequality is ≥, so includes "or equal to"
  • the second inequality is <, so <em>does not</em> include "or equal to"

3. Replace the inequality symbol with an equal sign and graph the resulting equation. If the "or equal to" case is included, the line is graphed as a solid line. If it is not, then the line is graphed as a dashed line.

  • the first equation (-x +y = -2) is graphed with a solid line
  • the second equation (y = (1/2)x +3) is graphed with a dashed line

4. It is not necessary, but is less confusing, to choose a variable in the inequality (after step 1) that has a <em>positive</em> coefficient. Notice whether this variable is "less than" or "greater than" the stuff on the other side of the inequality.

  • y ≥ . . . . for the first inequality
  • y < . . . or . . . x > . . . . for the second inequality

If it is less than, shade the portion of the graph below (for y <) or to the left (for x <) of the line you graphed in step 3.

  • the second inequality has y < , so the graph will be shaded <em>below</em> the dashed line. It also has x > , so will be shaded <em>to the right</em> of the dashed line. (These are the same shading.)

If it is greater than, shade the portion of the graph above (for y >) or to the right (for x >) of the line you graphed in step 3.

  • the first inequality has y ≥ , so the graph will be shaded <em>above</em> the solid line.

5. The solution set is where the shaded areas overlap. Any point on a dashed line is not in the solution set.

_____

The graph for the example inequalities is attached. The first one is graphed and shaded in red; the second one is graphed and shaded in blue.

6 0
3 years ago
WHAT IS THE RESULT WHEN 4׳+23ײ+21×+30÷×+5
puteri [66]

Answer:

grandma

Step-by-step explanation:

ur great great granddaddy

5 0
3 years ago
Help! I’m having lots of trouble
Pavlova-9 [17]
Area of parallelogram = b * h

                                      = 2 ft * 3.22 ft

                                      = 6.44 ft^2

Good luck :)
8 0
4 years ago
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