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Dmitrij [34]
3 years ago
14

Plutonium-241 is an isotope of plutonium that is highly radioactive and is used in some nuclear reactors and many nuclear

Chemistry
1 answer:
ikadub [295]3 years ago
5 0

Answer:

after 28.8 years 250 g of Pu-241 still remaining

Explanation:

Given data:

Total amount of Pu-241 = 1000 g

Half life = 14.4 years

Amount remaining after 28.8 years = ?

Solution:

Number of half lives = T elapsed / half life

Number of half lives = 28.8 years / 14.4 years

Number of half lives = 2

At time zero = 1000 g

At first half life = 1000 g/ 2 = 500 g

At second half life = 500 g/2 = 250 g

So after 28.8 years 250 g of Pu-241 still remaining.

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Mountains and hills form
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It felt good!!!

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Which is true with respect to the kinetic energy of a molecule?
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A.  it is the lowest at low temperatures

Explanation:

At low temperature the kinetic energy of a molecule is low. The kinetic energy is directly proportional to the temperature of the molecule. The kinetic energy of a molecule increases with the increase in the temperature that energize the molecules of a substance and makes them to move faster than before.

As the kinetic energy is proportional to temperature so it does not increase with decrease in the temperature (low temperature). The kinetic energy varies with the change in the temperature and it is not same at all temperature. The kinetic energy is highest at high temperature. Thus, option A is correct.

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3 years ago
You are given three cubes, A, B, and C; one is magnesium, one is aluminum, and the third is silver. All three cubes have the sam
katovenus [111]

Answer:

The cube A is magnesium, the cube B is aluminum and the cube C is silver.

Explanation:

Density is defined by the expression d=\frac{m}{V} where m is the mass and V is the volume, therefore:

- Density of the cube A:

d_{A}=\frac{m_{A}}{V_{A}}

- Density of the cube B:

d_{B}=\frac{m_{B}}{V_{B}}

- Density of the cube C:

d_{C}=\frac{m_{C}}{V_{C}}

Solving for mass:

m_{A}=d_{A}*V_{A}

m_{B}=d_{B}*V_{B}

m_{C}=d_{C}*V_{C}

And all the three cubes have the same mass, so:

m_{A}=m_{B}=m_{C}

Therefore:

d_{A}*V_{A}=d_{B}*V_{B} (Eq.1)

d_{A}*V_{A}=d_{C}*V_{C} (Eq.2)

Solving for d_{1} in Eq.1:

d_{A}=d_{B}\frac{V_{B}}{V_{A}}

Replacing values for the volume:

d_{A}=d_{B}\frac{16.7mL}{25.9mL}

d_{A}=d_{B}*0.64

As we know the density of the aluminum is 2.7\frac{g}{cm^{3}}, so replacing this value for d_{B}:

d_{A}=2.7\frac{g}{mL}*0.64

d_{A}=1.728\frac{g}{mL}

that is the density of the magnesium.

Solving for d_{C} in Eq.2:

d_{C}=d_{A}\frac{V_{A}}{V_{C}}

d_{C}=d_{A}\frac{25.9mL}{4.29mL}

d_{C}=d_{A}*6.04

d_{C}=1.728\frac{g}{mL}*6.04

d_{C}=10.4\frac{g}{mL}

That is the density of the silver.

Therefore the cube A is magnesium, the cube B is aluminum and the cube C is silver.

8 0
4 years ago
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