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2 years ago

What is the primary standard used in this experiment (name and formula)? define a secondary standard

Chemistry

1 answer:

kolbaska11 [484]2 years ago

4 0

Where is the experiment to define primary standard?? Then how do we answer your question?

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See picture below........................

kipiarov [429]

It's the reaction of molicules
hope this helps and mayb a brinaly? and if i get this wrong go to my pf and i will answer at least ten quesstions free!

6 0

2 years ago

Read 2 more answers

Ketones undergo a reduction when treated with sodium borohydride, NaBH4. The product of the above reaction has the following spe

Anna71 [15]

Answer:

The product is cyclohexanol

Explanation:

Firstly,

A ketone undergo a borohydride reduction reaction to form an alcohol as below,

R-CO-R' ⇒ R-CO(OH)-R'

IR Spectrum confirms that alcohol group is existed with the peak at 3400 cm⁻¹
From 1H-NMR, the product has 10 hydrogen atoms, the MS suggest that the formula is C₅H₁₀O (M = 86). With this formula, the alcohol is monosaturated. Since, the substance already underwent reduction reaction, the only way to suggest a monosaturated compound is a cyclic alcohol. So the compound is cyclopentanol.
Check with other spectroscopic properties,

3 signals of 13C NMR confirms the structure is symmetrical, δ 24.2, (-CH₂-CH₂-CH(CH₂-)-OH), δ 35.5 (-CH₂-CH₂-CH(CH₂-)-OH), δ 73.3 (-CH₂-CH₂-CH(CH₂-)-OH).

1H NMR confirms,

1.56 δ (4H, triplet) - (-CH₂-CH₂-CH-OH) ; triplet as coupling with 2 H,

1.78 δ (4H, multiplet) - (-CH₂-CH₂-CH-OH); multiplet as coupling with 2H of CH₂, 1 H of CH

3.24 δ (1H, quintet); - (-CH₂-CH₂-CH(CH₂-)-OH), coupling with4 H of 2 group of CH₂

3.58 δ (1H, singlet); - (-CH₂-CH₂-CH(CH₂-)-OH), hydrogen of alcohol group, not tend to coupling with other hydrogen

4 0

2 years ago

What do you look for when trying to identify a formula and/or compound name as ionic?

Yuri [45]

Answer:

Ionic compounds are named with the cation first and the anion last. The same convention is used when writing their chemical formulas.

Explanation:

4 0

2 years ago

What's the empirical and molecular weight of C14H22N4O8? What's the molecular formula of C14H22N4O8?

Inessa05 [86]

374u

187u

C₁₄H₂₂N₄O₈

Explanation:

To find the molecular weight of the compound C₁₄H₂₂N₄O₈ we simply sum that atomic masses of the given elements in the compound.

The empirical weight is determined by using the simplest ratio of the elements involved in the compound;

Molecular weight of C₁₄H₂₂N₄O₈;

atomic mass of C = 12g/mol

H = 1g/mol

N = 14g/mol

O = 16g/mol

Molecular weight = 14(12) + 22(1) + 4(14) + 8(16)

= 168 + 22 + 56 + 128

= 374u

Empirical weight:

Empirical formula:

C₁₄ H₂₂ N₄ O₈

14 : 22 : 4 : 8

divide by 2:

7 : 11 : 2 : 4

empirical formula C₇H₁₁N₂O₄

empirical weight = $\frac{molecular weight}{2}$ = $\frac{374}{2}$ = 187u

The molecular formula is the actual combination of atoms in a compound. so the molecular formula of the compound is C₁₄H₂₂N₄O₈

learn more:

Molecular mass brainly.com/question/5546238

#learnwithBrainly

8 0

2 years ago

If hydrogen were used as a fuel, it could be burned according to the following reaction: H2(g)+1/2O2(g)→H2O(g). Use average bond

serious [3.7K]

The deltaHrxn = -243 kJ/mol the deltaHrxn of CH4(methane) = -802 kJ/mol

The fuel that yields more energy per mole is METHANE. The negative sign merely signifies the release of energy. Thus, 802 kJ/mol is greater than 243 kJ/mol.

The fuel that yields more energy per gram is HYDROGEN. Here is the computation:
deltaHrxn = (-243 kJ/mol)(1 mol/2.016 g H2) = -120.535714286 kJ/g or -121 kJ/g

deltaHrxn of CH4(methane) = (-802 kJ/mol)(1 mol/16.04 g)
= -50 kJ/g

As discussed the negative sign serves as the symbol of released energy. Thus, 121 is greater than 50.

7 0

2 years ago