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Black_prince [1.1K]

3 years ago

7

If the formula for a compound is represented by XY2 and the charge on the Y ion is -2, what is the charge in the X ion? (2 point

s)
+1
+2
+3
+4

1 answer:

docker41 [41]3 years ago

6 0

Would it just be +1?
I'm not too sure, but that's the best guess I can come up with for you

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Given a fixed amount of gas in a rigid container (no change in volume), what pressure will the gas exert if the pressure is init

Masja [62]

Answer:

The pressure the gas will have if the pressure is initially 1.50 atm at 22.0 ° C and the temperature changes at 11.0 ° C is 1.44 atm (option D)

Explanation:

Gay Lussac's law indicates that, as long as the volume of the container containing the gas is constant, as the temperature increases, the gas molecules move more rapidly. Then the number of collisions against the walls increases, that is, the pressure increases. That is, the gas pressure is directly proportional to its temperature.

Gay-Lussac's law can be expressed mathematically as follows:

$\frac{P}{T}=k$

Where P = pressure, T = temperature, K = Constant

You have a gas that is at a pressure P1 and at a temperature T1. When the temperature varies to a new T2 value, then the pressure will change to P2, and then:

$\frac{P1}{T1}=\frac{P2}{T2}$

In this case:

P1= 1.50 atm
T1= 22 °C= 295 °K (being 0°C= 273 °K)
P2= ?
T2= 11 °C= 284 K

Replacing:

$\frac{1.5 atm}{295 K}=\frac{P2}{284 K}$

Solving:

$P2= 284 K*\frac{1.5 atm}{295 K}$

P2=1.44 atm

<u><em>The pressure the gas will have if the pressure is initially 1.50 atm at 22.0 ° C and the temperature changes at 11.0 ° C is 1.44 atm (option D)</em></u>

8 0

3 years ago

What volume of 0.305 m agno3 is required to react exactly with 155.0 ml of 0.274 m na2so4 solution? hint: you will want to write

LuckyWell [14K]

The balanced chemical equation for reaction of $AgNO_{3}$ and $Na_{2}SO_{4}$ is as follows:

$2 AgNO_{3}+Na_{2}SO_{4}\rightarrow 2NaNO_{3}+Ag_{2}SO_{4}$

From the balanced chemical equation, 2 mol of $AgNO_{3}$ reacts with 1 mol of $NaNO_{3}$ .

First calculating number of moles of $NaNO_{3}$ as follows:

$M=\frac{n}{V}$

On rearranging,

$n=M\times V$

Here, M is molarity and V is volume. The molarity of $NaNO_{3}$ is given 0.274 M or mol/L and volume 155 mL, putting the values,

$n=0.274 mol/L\times 155\times 10^{-3}mL=0.04247 mol$

Since, 1 mol of $NaNO_{3}$ reacts with 2 mol of $AgNO_{3}$ thus, number of moles of $AgNO_{3}$ will be $2\times 0.04247 mol=0.08494 mol$ .

Now, molarity of $AgNO_{3}$ is given 0.305 M or mol/L thus, volume can be calculated as follows:

$V=\frac{n}{M}=\frac{0.08494 mol}{0.305 mol/L}=0.2785 L=278.5 mL$

Therefore, volume of $AgNO_{3}$ is 278.5 mL.

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4 years ago

Please answer this question

lukranit [14]

I think it will be B. Hope it helps :)

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3 years ago

Are all molecules of a particular substance alike?

STALIN [3.7K]

Answer:

Yes.

Explanation:

Yes, all molecules of a particular substance are similar or alike if the substance has similar shape and structure. Molecule is made up of two or more atoms having no charge on them and the atoms present in it make bonds with each other. For example, water is made of similar molecules i. e. two hydrogen atom and one oxygen atom bonded together with a covalent bond.

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iVinArrow [24]

Answer:

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Explanation:

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