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2 years ago

6

Derivative of sin11xcos11x

1 answer:

diamong [38]2 years ago

6 0

Hello here is a solution :
f'(x) =( sin11x)'cos11x +<span>sin11x(cos11x)'
(sin(ax+b))'=a cos(ax+b)
</span>(cos(ax+b))'=-a sin(ax+b)
f'(x) = 11 cos11xcos11x-11sin11xsin11x
f'(x) = 11(cos11x)²-11(sin11x)²

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<u>Answer:</u>

D) 6x^2 - 8y^2 = 50

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<u>Step-by-step explanation:</u>

We are given the following two expressions:

$3x^2-4y^2=25$

and

$-6x^2-2y^2=11$

Now if we look at the option D) $6x^2 - 8y^2 = 50
$ and $-6x^2 - 2y^2 = 11$ , we can observe that the earlier part in the given expression is just a simplification of 6x^2 - 8y^2 = 50.

$6x^2 - 8y^2 = 50\\\\2(3x^2-4y^2) = 50\\\\3x^2-4y^2 = \frac{50}{2} \\\\3x^2-4y^2=25$

and the later part $-6x^2 - 2y^2 = 11$ is already the same.

Therefore, the correct answer option is D) 6x^2 - 8y^2 = 50

-6x^2 - 2y^2 = 11.

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