Answer:
one mole of HgO will give one mole of Hg.
Explanation:
Given data:
Moles of HgO = 1 mol
Moles of Hg = ?
Solution:
Chemical equation:
2HgO → 2Hg + O₂
Now we will compare the moles of Hg with HgO from balance chemical equation.
HgO : Hg
2 : 2
1 : 2/2×1 = 1 mol
So, one mole of HgO will give one mole of Hg.
Answer:
Adding H₂O(g) to the system.
Explanation:
- Le Châtelier's principle states that when there is an dynamic equilibrium, and this equilibrium is disturbed by an external factor, the equilibrium will be shifted in the direction that can cancel the effect of the external factor to reattain the equilibrium.
<u><em>1) Removing H₂O(g) from the system:</em></u>
- This will decrease the concentration of the reactants side, so the reaction will be shifted to the left side to suppress the removal of H₂O(g) from the system.
<u><em>2) Adding CH₃CHO(g) to the system :</em></u>
- This will increase the concentration of the products side, so the reaction will be shifted to the left side to suppress the adding CH₃CHO(g) to the system.
<u><em>3) Removing C₂H₂(g) from the system:</em></u>
- This will decrease the concentration of the reactants side, so the reaction will be shifted to the left side to suppress the removal of C₂H₂(g) from the system.
<u><em>4) Adding H₂O(g) to the system:</em></u>
- This will increase the concentration of the reactants side, so the reaction will be shifted to the right side to suppress the addition of H₂O(g) to the system.
- <u><em>So, it is the right choice.</em></u>
Answer:
In Beryllium there are two energy levels
Explanation:
<u>Answer:</u> The volume of carbon dioxide gas at STP for given amount is 106.624 L
<u>Explanation:</u>
We are given:
Moles of carbon dioxide = 4.76 moles
<u>At STP:</u>
1 mole of a gas occupies a volume of 22.4 Liters
So, for 4.76 moles of carbon dioxide gas will occupy a volume of = 
Hence, the volume of carbon dioxide gas at STP for given amount is 106.624 L
B.. it is a combination reaction... A + B--> AB