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3 years ago

Which of the following types of radiation can penetrate the most deeply into your body?

Chemistry

2 answers:

ra1l [238]3 years ago

8 0

Proton rays are the rays which can penetrate the most deeply into our body.

Answer: D

Explanation

The radiations are surrounding our atmosphere.

The radiations like alpha rays cannot penetrate dead skin cells while the beta rays can penetrate up to some layers of the skin.

The gamma rays are not a beam of energetic particles like alpha and beta rays, they are beam of energies released in order to stabilize the daughter nuclei.

But the rays which can penetrate more deeply in human body is proton rays and X-rays.

The proton rays are the beam of energetic protons which are positively charged.

They are heavy beam of energies.

The proton rays can penetrate the skin as well as reach the damage cells or tumor cells and they can cure them using proton therapy.

ivolga24 [154]3 years ago

6 0

Answer:

gamma rays

Explanation:

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A car at rest ends accelerates for 12 seconds. After this time the car is going 36 m/s. What was its acceleration?

Zigmanuir [339]

Acceleration is defined as velocity per unit time.

$Acceleration=\frac{Velocity}{time}$

$a=\frac{dv}{dt}$

Here, a=acceleartion,

v=velocity=36 m/s

t=time=12 s

$a=\frac{dv}{dt}$

$a=\frac{36}{12}$

$a=3 ms⁻²$

A car at rest ends accelerates for 12 seconds. After this time the car is going 36 m/s. So acceleration that is a=3 ms⁻².

4 0

3 years ago

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Please comment if you are sure about your answer . Thank you

ryzh [129]

2,3,7,10,13 i did this yesterday can u mark me brainliest

3 0

3 years ago

5. Which statement is true about electronegativity?

Anit [1.1K]

Answer:

Electronegativity generally increases from left to right across a period,

Explanation:

The true statement from the given choices is that electronegativity generally increases from left to right across a period.

Electronegativity is the measure of the relative tendency with which an atom of the element attract valence electrons in a chemical bond.

Across a period electronegativity increases from left to right and decreases down the group.

This is due to reduction in metallic properties as we move across the period from left to right.

3 0

2 years ago

Use the information provided to determine ΔH°rxn for the following reaction: ΔH°f (kJ/mol) 3 Fe2O3(s) + CO(g) → 2 Fe3O4(s) + CO2

zepelin [54]

Answer:

ΔH°rxn = -47 kJ

Explanation:

Using Hess´s law for the reaction:

3 Fe2O3(s) + CO(g) → 2 Fe3O4(s) + CO2(g) ,

the ΔH°rxn will be given by the expression:

ΔH°rxn kJ = 2ΔHºf(Fe3O4) + ΔHºf(CO2) - ( 3ΔHºf(Fe2O3) + ΔHºf(CO) )

= 2(-1118) + (-394) - ( 3( -824 ) + ( -111 ) )

= - 47 kJ

3 0

3 years ago

Read 2 more answers

In which of the following reactions does a decrease in the volume of the reaction vessel at constant

Black_prince [1.1K]

Answer:

The correct option is: A) 2H₂(g) + O₂(g) → 2H₂O(g)

Explanation:

According to the Le Chatelier's principle, change in the volume of the reaction system causes equilibrium to shift in the direction that reduces the effect of the volume change.

When the volume decreases then the pressure of the reaction vessel increases, then the equilibrium shifts towards the reaction side that produces less number of moles of gas.

A) 2H₂(g) + O₂(g) → 2H₂O(g)

The number of moles of reactant is 3 and number of moles of product is 2.

Therefore, when volume decreases, the equilibrium shifts towards the product side, thereby favoring the formation of products.

B) NO₂(g) + CO(g) → NO(g) + CO₂(g)

The number of moles of reactant and product both is 2.

Therefore, when the volume decreases, the equilibrium does not shift in any direction.

C) H₂(g) + I₂(g) → 2HI(g)

The number of moles of reactant and product both is 2.

Therefore, when the volume decreases, the equilibrium does not shift in any direction.

D) 2O₃(g) → 3O₂(g)

The number of moles of reactant is 2 and number of moles of product is 3.

Therefore, when volume decreases, the equilibrium shifts towards the reactant side, thereby favoring the formation of reactants.

E) MgCO₃(s) → MgO(s) + CO₂(g)

The number of moles of reactant is 1 and number of moles of product is 2.

Therefore, when volume decreases, the equilibrium shifts towards the reactant side, thereby favoring the formation of reactants.

6 0

3 years ago