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kogti [31]
3 years ago
14

4. Based on their placement on the periodic table, which of the following is more

Chemistry
1 answer:
sukhopar [10]3 years ago
7 0
Ur answer is A! Sodium
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A 5.0 L sample of gas at 300. K is heated to 600. K. What will the new volume of the gas be?
Ainat [17]

Answer:

V_2=10L

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to calculate the required new volume by using the Charles' law as a directly proportional relationship between temperature and volume:

\frac{V_2}{T_2} =\frac{V_1}{T_1}

In such a way, we solve for V2 and plug in V1, T1 and T2 to obtain:

V_2=\frac{V_1T_2}{T_1}\\\\V_2=\frac{5.0L*600K}{300K}\\\\V_2=10L

Regards!

4 0
3 years ago
What is formed when hydrobromic acid, hbr, and calcium hydroxide, ca(oh)2, are combined?
Lorico [155]

This is an acid – base reaction and this always result a salt and water in a neutralization reaction. <span>

The salt that is formed will be calcium bromide (calcium is located in group 2 so calcium bromide has a formula of CaBr2) 

so essentially we got:

HBr + Ca(OH)2 ------> CaBr2 + H2O </span>

balancing the elements: <span>

<span>2HBr(aq) + Ca(OH)2(aq) --------> CaBr2(aq) + 2H2O(l)</span></span>

6 0
3 years ago
(a) Show that the pressure exerted by a fluid P (in pascals) is given by P = hdg, where h is the column of the fluid in metres,
Komok [63]

Answer:

B) THE DEPTH OF THE LAKE IS 0.060 m

Explanation:

b) Determine the depth of the lake in metres

1. Using the general gas law, we will calculate the initial pressure of the air bubbles.

P1V1 /T1 = P2V2/T2

P1 = Unknown

T1 = 5.24 °C

T2 = 18.73 °C

P2 = 0.973 atm

V1 = V1

V2 = 6V1

P1 = P2 V2 T1 / V1 T2

P1 = 0.973 * 6V1 * 5.24 / V1 * 18.73

P1 = 5.09852 * 6 / 18.73

P1 = 30.59112 / 18.73

P1 = 1.633 atm.

2. Calculate the depth of the lake:

             Pressure = length * density * acceleration

            length = Pressure / density * acceleration

Pressure = 1.633 atm = 1.633 * 101, 325 Nm^2 = 165, 463.725 Nm^2

Density =  1.02 g/cm3 = 1.02 * 10^3 kg/m^3

Acceleration = 9.8 m/s^2

So therefore, the length in metres is:

Length = density * acceleration / pressure

Length =  1.02 *10^3 * 9.8 / 165, 463.725  

Length = 9.996 * 10^3 / 165 463.725

Length = 0.06 m

Hence, the depth of the lake is 0.06 m

6 0
3 years ago
Imagine that you have a metal bar sitting half in the sun and half in the dark. On a sunny day, the part of the metal that has b
babunello [35]

Answer:

It will feel hot.

Explanation:

The part of the metal that has been sitting in the sun will heat up, and because metal is a good conductor,<em> the part sitting in the sun will heat up the part sitting in the dark</em>.

We say metal is a good conductor because it has<em> high thermal conductivity</em>, which mean heat will flow from the hot section of the bar to the cold section of the bat.

6 0
3 years ago
In the gas-phase reaction 2 A + B ⇌ 3 C + 2 D, it was found that, when 1.00 mol A, 2.00 mol B, and 1.00 mol D were mixed and all
Naddik [55]

Answer:

(i)The mole fractions are :

  • A=\frac{0.4}{4.3} \\=0.0930
  • B=\frac{1.4}{4.3} \\=0.3256
  • C=\frac{0.9}{4.3} \\=0.2093
  • D=\frac{1.6}{4.3} \\=0.3721

(ii)K=0.4508

(iii)ΔG = 1.974kJ

Explanation:

The given equation is :

2A+B⇄3C+2D

Let \alpha be the number of moles dissociated per mole of B

Thus ,

<em>The initial number of moles of :</em>

  • A=1
  • B=2
  • C=0
  • D=1

2A\\(1-2\alpha)     +  B\\2(1-\alpha)  ⇄  3C\\(3\alpha)   + 2D\\(1+2\alpha)

And finally the number of moles of C[tex] is 0.9Thus ,[tex]3\alpha=0.9\\\alpha=0.3[tex]The final number of moles of:[tex]A = 1-2\alpha=1-2*0.3=0.4mol[tex] [tex]B=2(1-\alpha)=2(1-0.3)=1.4mol[tex][tex]D=1+2\alpha=1+2*0.3=1.6mol[tex]Thus , total number of moles are : 0.4+1.4+0.9+1.6=4.3(i)The mole fractions are : [tex]A=\frac{0.4}{4.3} \\=0.0930

  • B=\frac{1.4}{4.3} \\=0.3256
  • C=\frac{0.9}{4.3} \\=0.2093
  • D=\frac{1.6}{4.3} \\=0.3721

(ii)

K=\frac{(P_C^3)(P_D^2)}{(P_A^2)(P_B)}

Where ,

P_A,P_B,P_C,P_D are the partial pressures of A,B,C,D respectively.

Total pressure = 1 bar .

∴

<em>P_A= 0.0930*1=0.0930</em>

<em>P_B= 0.3256*1=0.3256</em>

<em>P_C= 0.2093*1=0.2093</em>

<em>P_D= 0.3721*1=0.3721</em>

K=\frac{0.2093^3*0.3721^2}{0.0930^2*0.3256} \\K=0.4508

(iii)

ΔG=-RTlnK\\

ΔG = -8.314*(273+25)*ln(0.4508)\\=1973.96J\\=1.974kJ

3 0
3 years ago
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