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kenny6666 [7]
3 years ago
5

Consider the energy diagram below.

Chemistry
2 answers:
Kazeer [188]3 years ago
4 0

Answer:

A) The catalyzed reaction passes through C.

Explanation:

nordsb [41]3 years ago
3 0

Answer:

The catalyzed reaction passes through C.

Explanation:

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Solid liquid and gas is the answer
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By definition, a solution containing a large number of H3O+ ions is best defined as _________.
Vadim26 [7]
A large quantity if hydronium ions indicates an Arrhenius acid.
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A(n) _____________ is a mixture of fuel and oxygen for which the masses of these two components are exactly those needed for com
aev [14]

A stoichiometric mixture is a mixture of fuel and oxygen for which the masses of these two components are exactly those needed for complete combustion.

A stoichiometric mixture is a balanced mixture of fuel and oxygen.

The fuel and the oxygen react completely without the excesses of either.

The opposite of a stoichiometric mixture is called feeding an excess, when minimum one reactant is an excess amount.

Balanced chemical equation for reaction of combustion one type of a fuel: C₈H₁₈ + 25/2O₂ → 8CO₂ + 9H₂O

Stoichiometric mixture for this example is when fuel (C₈H₁₈) and oxygen(O₂) react in proportion 1 : 12.5.

More about a stoichiometric mixture: brainly.com/question/19585982

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6 0
2 years ago
How much heat is absorbed by 15.5g of water when it's temperature is increased from 20.0C the specific heat of the water is 4.18
Anuta_ua [19.1K]
Hello!

The exercise doesn't say the final temperature, but we are going to assume that the increase is of 20 °C (The procedure is the same, just change the final temperature) To calculate the heat absorbed by water, we need to use the equation for Heat Transfer, in the following way (assuming that the heat increase is 20°C):

Q=m*C* \Delta T=15,5 g * 4,184 (J/g^\circ C) * 20 ^\circ C=1297,04 J

So, the Heat absorbed by water is 1297,04 J

Have a nice day!
7 0
3 years ago
Think about the decomposition reaction of ozone.
____ [38]

Answer:

3441.6 grams.

Explanation:

2 O₃ → 3 O₂

First we <u>convert 71.7 moles of ozone (O₃) into moles of oxygen gas (O₂)</u>, using the <em>stoichiometric coefficients</em> of the reation:

71.7 mol O₃ * \frac{3molO_2}{2molO_3} = 107.55 mol O₂

Then we <u>convert 107.55 moles of O₂ into grams</u>, using the <em>molar mass of O₂</em>:

107.55 mol * 32 g/mol = 3441.6 g

3 0
3 years ago
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