A Merit Rating System for SUTA means:

Mathematics

2 answers:

Zepler [3.9K]4 years ago

5 0

Answer: from my text book it say;

"some states offer a merit rating system that results in a lower SUTA rate for companies with a stable employment period".

Step-by-step explanation:

VladimirAG [237]4 years ago

4 0

The concept is to reward employers that keep employees around. With less turn over, the unemployment fund is used less frequently and it costs the system less money.

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Hatshy [7]

Answer:

1, 3, and 4 would be correct answers

Step-by-step explanation:

1.) -x - 2x - 3y - 2y + 1 + 1 = -3x -5y + 2

2.) -3x + 2y + 3y + 2 = -3x + 5y + 2

3.) -3x - y - y - y - y - y + 2 = -3x - 5y + 2

4.) -x - x - x - y - y - y - y - y + 1 + 1 = -3x - 5y + 2

5.) x + x + x + y + y + y + y + y + 1 + 1 = 3x + 5y + 2

Hope this helps!

5 0

3 years ago

A restaurant offers a catering service which costs $25.00 per person with a $119.50 service charge. For parties of 50 or more pe

Molodets [167]

Answer:

T1(n) = 25n +119.50 where n belongs to $1 \leq n$ .

T2(n) = 20n + 59 where n belongs to $50\leq n$ .

Step-by-step explanation:

We are given two situations first is for normal days and the other is for days when 50 or more people are going to this restaurant for the party.

Let the number of person going for this restaurant be "n"

For normal day, we are given

catering service = $25 per person

service charge = $119.50

Let the total cost of the restaurant be T

Cost for this case will be T1

T1(n) = 25n +119.50 where n belongs to $1 \leq n$

similarly for the case when 50 or more than that goes to this restaurant for party.

cost after discount

Catering service = $20.00 per person

service charge = $59.00

now the cost of this case will be T2

T2(n) = 20n + 59 where n belongs to $50\leq n$ .

Therefore the two piecewise linear functions represents the total cost of the restaurant for serving n people.

7 0

3 years ago

Derive identity sin(3x) = 3 sinx−4 sin³x

sesenic [268]

$sin3x=3sinx-4sin^3x\\\\L=sin(2x+x)=sin2xcosx+sinxcos2x\\\\=2sinxcosxcosx+sinx(cos^2x-sin^2x)\\\\=2sinxcos^2x+sinxcos^2x-sin^3x\\\\=3sinxcos^2x-sin^3x\\\\=3sinx(1-sin^2x)-sin^3x\\\\=3sinx-3sin^3x-sin^3x\\\\=3sinx-4sin^3x=R$